我有它的工作。但是,最初它似乎在等待输入。如何在停止并等待输入之前读取输出内容?
task starts
stdout should post data for "sftp> " but nothing happens, its waiting for input
If I write "\n" to stdin
stdout notifies me of data available which ends up being "sftp> \n"
以下是它的实施方式:
[self.task = [[NSTask alloc] init];
[self.task setLaunchPath:executablePath];
[self.task setArguments: args];
[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(terminatedNotification:) name:NSTaskDidTerminateNotification object:self.task];
//reading
self.stdoutPipe = [NSPipe pipe];
self.task.standardOutput = self.stdoutPipe;
[self.stdoutPipe.fileHandleForReading waitForDataInBackgroundAndNotify];
//error
self.stderrorPipe = [NSPipe pipe];
self.task.standardError = self.stderrorPipe;
[self.stderrorPipe.fileHandleForReading waitForDataInBackgroundAndNotify];
/*
reading works perfect until I uncomment this section
//writing
self.stdinPipe = [NSPipe pipe];
self.task.standardInput = self.stdinPipe;
*/
[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(dataAvailable:) name:NSFileHandleDataAvailableNotification object:self.stdoutPipe.fileHandleForReading];
[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(dataAvailable:) name:NSFileHandleDataAvailableNotification object:self.stderrorPipe.fileHandleForReading];
答案 0 :(得分:3)
写入NSFileHandle的数据被缓冲。只有在刷新缓冲区后,它才能在管道的另一端读取。如果
,则刷新缓冲区- (void)synchronizeFile