Question

<?xml version="1.0"?>
<AppXmlLogWritter>
  <LogData>
    <LogID>5678201301161640382919</LogID>
    <LogDateTime>20130114164038</LogDateTime>            
  </LogData>
  <LogData>
    <LogID>5678201301161640382920</LogID>
    <LogDateTime>20130115154040</LogDateTime>           
  </LogData>
  <LogData>
  <LogID>5678201301161640382921</LogID>
  <LogDateTime>20130116164042</LogDateTime>          
  </LogData>
</AppXmlLogWritter>

删除我在xpath查询

下面使用的一个节点

string xpathQuery = "/AppXmlLogWritter/LogData[LogDateTime ='" + txtToDate.Text.Trim() + "']";
XmlNodeList objxmlNodeList = objXmldoc.SelectNodes(xpathQuery);
for (int i = 0; i <= objxmlNodeList.Count - 1; i++)
{
    objxmlNodeList[i].ParentNode.RemoveChild(objxmlNodeList[i]);
    lblMessage.Text = "Record deleted sucessfully.";
}

我正在编写各种应用程序的XML文件。用户可以在LogDateTime的范围之间删除日志.How是我的XPath查询，用于删除LogDateTime范围之间的日志。

示例：如果我必须删除日期时间范围20130116164038到20130116164040之间的日志。

Answer 1

试试这个：

strXpathQuery = "/AppXmlLogWritter/LogData[LogDateTime >='" + txtFromDate.Text.Trim() + "' and LogDateTime <='" + txtToDate.Text.Trim() +"']";

要在指定日期获取所有logdata，您可以使用：

strXpathQuery = "/AppXmlLogWritter/LogData[starts-with(LogDateTime, '20130116')]";

要获得logdata范围内从{20130114'到'20130116'的所有LogDateTime，您可以使用此功能：

strXpathQuery = "/AppXmlLogWritter/LogData[substring(LogDateTime, 1, 8) >='20130114' and substring(LogDateTime, 1, 8) <='20130116']";

查询以删除logdatetime范围之间的日志

1 个答案: