Question

以下查询不显示余额数量，其中有内部余额，我也想要每天的数据：

SELECT I.Date as Date, 
P.ResourceName as ItemName,
P.ResourceRate as Rate,
i.TotalInQty as InwardsQuantity,
s.TotalOutQty as OutwardsQuantity,
i.TotalInQty-S.TotalOutQty as Balance,
O.UnitSymbol As ItemUnit
FROM UnitMaster O
INNER JOIN Resource_Master P
 ON O.UnitCode = P.Unitcode
LEFT JOIN
(
  select COALESCE(sum(i.Qty), 0) AS TotalInQty, Nameofitem, Min(I.Date) AS Date
  from Inwards_Master I
  group by Nameofitem
) I
ON I.Nameofitem= P.ResourceName
LEFT JOIN
(
  select COALESCE(sum(s.qty), 0) AS TotalOutQty, Nameofitem, Min(S.Date) AS Date
  from Outwards_Master S 
  group by s.Nameofitem
) S
ON I.Date=S.Date 
AND I.Nameofitem =S.Nameofitem
WHERE P.TenderCode=1

任何机构都可以对此有所了解吗？

Answer 1

我怀疑第一个问题是您在错误的级别使用COALESCE - 您实际想要做的是消除由于NULL不成功而产生的LEFT JOIN 。您无法消除子查询中的NULL，因为它在该行集中不存在：

SELECT I.Date as Date, 
P.ResourceName as ItemName,
P.ResourceRate as Rate,
COALESCE(i.TotalInQty,0) as InwardsQuantity,
COALESCE(s.TotalOutQty,0) as OutwardsQuantity,
COALESCE(i.TotalInQty,0)-COALESCE(S.TotalOutQty,0) as Balance,
O.UnitSymbol As ItemUnit
FROM UnitMaster O
INNER JOIN Resource_Master P
 ON O.UnitCode = P.Unitcode
LEFT JOIN
(
  select sum(i.Qty) AS TotalInQty, Nameofitem, Min(I.Date) AS Date
  from Inwards_Master I
  group by Nameofitem
) I
ON I.Nameofitem= P.ResourceName
LEFT JOIN
(
  select sum(s.qty) AS TotalOutQty, Nameofitem, Min(S.Date) AS Date
  from Outwards_Master S 
  group by s.Nameofitem
) S
ON I.Date=S.Date 
AND I.Nameofitem =S.Nameofitem
WHERE P.TenderCode=1

Answer 2

试试这个：

SELECT I.Date as Date,
P.ResourceName as ItemName,
P.ResourceRate as Rate,
COALESCE(i.TotalInQty,0) as InwardsQuantity,
--s.TotalOutQty as OutwardsQuantity,
COALESCE(s.TotalOutQty,0) as OutwardsQuantity,
--i.TotalInQty-s.TotalOutQty as Balance,
COALESCE(i.TotalInQty,0)-COALESCE(S.TotalOutQty,0) as Balance,
O.UnitSymbol As ItemUnit 
FROM UnitMaster O 
INNER JOIN Resource_Master P 
    ON O.UnitCode = P.Unitcode 
    LEFT JOIN(select sum(i.Qty) AS TotalInQty,Nameofitem,Min(I.Date) AS Date  from Inwards_Master I where Tendercode=1 group by Nameofitem) I ON I.Nameofitem= P.ResourceName 
    LEFT JOIN(select sum(s.qty) AS TotalOutQty,Nameofitem, Min(S.Date) AS Date  from Outwards_Master S where Tendercode=1 group by s.Nameofitem) S ON I.Date=S.Date AND I.Nameofitem =S.Nameofitem 
WHERE P.Status=1 and P.TenderCode= 1

显示每天库存中可用库存的余额

2 个答案: