这是一个非常正常的SQL查询:
DECLARE @IncludePTO AS CHAR
SET @IncludePTO = 'Y'
SELECT
HQCO.HQCo, HQCO.Name, PREH.PRDept, PREH.Craft, HRRM.PositionCode, PRTH.Employee,
PREH.LastName, PREH.FirstName, SUM(PRTH.Hours) AS Hrs
FROM PREH
INNER JOIN HRRM ON PREH.PRCo = HRRM.HRCo AND PREH.Employee = HRRM.HRRef
INNER JOIN PRTH ON PREH.PRCo = PRTH.PRCo AND PREH.Employee = PRTH.Employee
INNER JOIN HQCO ON PRTH.PRCo = HQCO.HQCo
WHERE
(dbo.PRTH.PREndDate BETWEEN '1/1/2012 00:00:00' AND '1/1/2013 00:00:00')
AND (PRGroup = 2)
AND dbo.PRTH.EarnCode IN (1,3,8)
GROUP BY
HQCO.HQCo, HQCO.Name, PREH.PRDept, PREH.Craft,
HRRM.PositionCode, PRTH.Employee, PREH.LastName, PREH.FirstName
但是,我试图在WHERE子句中使用'IN'谓词和CASE WHEN。看看下面的修改后的查询:
DECLARE @IncludePTO AS CHAR
SET @IncludePTO = 'Y'
SELECT
HQCO.HQCo, HQCO.Name, PREH.PRDept, PREH.Craft, HRRM.PositionCode, PRTH.Employee,
PREH.LastName, PREH.FirstName, SUM(PRTH.Hours) AS Hrs
FROM PREH
INNER JOIN HRRM ON PREH.PRCo = HRRM.HRCo AND PREH.Employee = HRRM.HRRef
INNER JOIN PRTH ON PREH.PRCo = PRTH.PRCo AND PREH.Employee = PRTH.Employee
INNER JOIN HQCO ON PRTH.PRCo = HQCO.HQCo
WHERE
(dbo.PRTH.PREndDate BETWEEN '1/1/2012 00:00:00' AND '1/1/2013 00:00:00')
AND (PRTH.PRGroup = 2)
AND
CASE WHEN @IncludePTO = 'Y' THEN dbo.PRTH.EarnCode IN (1,2,3,8,100,110,120,115)
ELSE dbo.PRTH.EarnCode IN (1,2,3,8)
END
GROUP BY
HQCO.HQCo, HQCO.Name, PREH.PRDept, PREH.Craft, HRRM.PositionCode, PRTH.Employee,
PREH.LastName, PREH.FirstName
它似乎不起作用并且一直给我一个语法错误:
Msg 156,Level 15,State 1,Line 15
关键字“IN”附近的语法不正确。
指出我缺少什么的任何帮助或指导?我非常感谢任何帮助/提示..非常感谢,
Pranav
答案 0 :(得分:3)
你是对的。不允许使用语法。你可以尝试:
((@IncludePTO = 'Y' and dbo.PRTH.EarnCode IN (1,2,3,8,100,110,120,115)) or
(@IncludePTO <> 'Y' and dbo.PRTH.EarnCode IN (1,2,3,8))
)
这可以简化为:
(bo.PRTH.EarnCode IN (1,2,3,8) or (@IncludePTO <> 'Y' and dbo.PRTH.EarnCode IN (100,110,120,115))
)
这假设@IncludePTO永远不会为NULL。如果是这样,则必须参加测试。
如果确实想要where
子句中的case语句,您可以这样做:
(CASE WHEN @IncludePTO = 'Y' and dbo.PRTH.EarnCode IN (1,2,3,8,100,110,120,115)
then 'true'
when @IncludePTO <> 'Y' and dbo.PRTH.EarnCode IN (1,2,3,8)
then 'true'
else 'false'
end) = 'true'