Question

我正在尝试将一个int值从我的Service传递给CallReceiver类，不幸的是CallReceiver.value总是等于0，即使在设置了另一个值之后也是如此。当我试图将它作为参数传递给构造函数时，情况完全相同，因此使用从service调用的setter方法。真的没有办法传递任何数据吗？

服务：

SharedPreferences settings = getSharedPreferences("SETTINGS", 0);
    int value = settings.getInt("value1", 0); // here the correct value is present, not 0.
    CallReceiver mCallReceiver = new CallReceiver();
    CallReceiver.value = value;

接收器：

public class CallReceiver extends BroadcastReceiver  {

public int value;

public CallReceiver(int value)  {
    this.value = value;
}

public CallReceiver()   {

}


@Override
public void onReceive(Context context, Intent intent) {


            Log.v("value", String.valueOf(value)); // here "value" = 0.


        }

     }

Answer 1

您的CallReceiver mCallReceiver=new CallReceiver();实例不用于接收意图。相反，Android每次都会创建新实例。 0是未初始化的整数变量的默认值。

要确保发生这种情况，请为value字段指定一些默认值：

public class RReceiver extends BroadcastReceiver {
    public int value=5;
    //...
}

，你的价值总是等于5。

至于将数据传递到BroadcastReceiver，请将其添加为您正在广播的Intent的额外内容：

//in your service
Intent broadcastedIntent=new Intent(this, CallReceiver.class);
broadcastedIntent.putExtra("VALUE", 100500);
sendBroadcast(broadcastedIntent);

然后，在CallReceiver：

中

@Override
public void onReceive(Context context, Intent intent) {
    int value=intent.getIntExtra("VALUE", 0);
}

将参数传递给BroadcastReceiver

1 个答案: