我有以下阵列:
$front = array("front_first","front_second");
$inside = array("inside_first", "inside_second", "inside_third");
$back = array("back_first", "back_second", "back_third","back_fourth");
我需要做的是将它组合起来,以便在上述情况下输出看起来像这样。输出顺序始终是按顺序back, front, inside
:
$final = array(
"back_first",
"front_first",
"inside_first",
"back_second",
"front_second",
"inside_second",
"back_third",
"front_second",
"inside_third",
"back_fourth",
"front_second",
"inside_third"
);
所以基本上它会查看三个数组,并且无论哪个数组具有较少的值,它都会多次重复使用最后一个值,直到它遍历较长数组中的其余键为止。
有办法做到这一点吗?我很难过/
答案 0 :(得分:3)
$front = array("front_first","front_second");
$inside = array("inside_first", "inside_second", "inside_third");
$back = array("back_first", "back_second", "back_third","back_fourth");
function foo() {
$args = func_get_args();
$max = max(array_map('sizeof', $args)); // credits to hakre ;)
$result = array();
for ($i = 0; $i < $max; $i += 1) {
foreach ($args as $arg) {
$result[] = isset($arg[$i]) ? $arg[$i] : end($arg);
}
}
return $result;
}
$final = foo($back, $front, $inside);
print_r($final);
答案 1 :(得分:2)
演示
http://codepad.viper-7.com/xpwGha
PHP
$front = array("front_first", "front_second");
$inside = array("inside_first", "inside_second", "inside_third");
$back = array("back_first", "back_second", "back_third", "back_fourth");
$combined = array_map("callback", $back, $front, $inside);
$lastf = "";
$lasti = "";
$lastb = "";
function callback($arrb, $arrf, $arri) {
global $lastf, $lasti, $lastb;
$lastf = isset($arrf) ? $arrf : $lastf;
$lasti = isset($arri) ? $arri : $lasti;
$lastb = isset($arrb) ? $arrb : $lastb;
return array($lastb, $lastf, $lasti);
}
$final = array();
foreach ($combined as $k => $v) {
$final = array_merge($final, $v);
}
print_r($final);
输出
Array
(
[0] => back_first
[1] => front_first
[2] => inside_first
[3] => back_second
[4] => front_second
[5] => inside_second
[6] => back_third
[7] => front_second
[8] => inside_third
[9] => back_fourth
[10] => front_second
[11] => inside_third
)