我有用户为他们的表单命名各种疯狂的东西,但我希望能够获得Excel文档的第一张,无论它的名称是什么。
我目前使用:
OleDbDataAdapter adapter = new OleDbDataAdapter(
"SELECT * FROM [sheetName$]", connString);
无论名称是什么,我如何获得第一张?
谢谢。
答案 0 :(得分:27)
最终使用了这个:
using (OleDbConnection conn = new OleDbConnection(connString))
{
conn.Open();
dtSchema = conn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, new object[] { null, null, null, "TABLE" });
Sheet1= dtSchema.Rows[0].Field<string>("TABLE_NAME");
}
答案 1 :(得分:15)
OleDbConnection oconn = new OleDbConnection(@"Provider=Microsoft.ACE.OLEDB.12.0;Data Source="Path"; Extended Properties=Excel 12.0;Persist Security Info=False;");
oconn.Open();
myCommand.Connection = oconn;
DataTable dbSchema = oconn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, null);
if (dbSchema == null || dbSchema.Rows.Count < 1)
{
throw new Exception("Error: Could not determine the name of the first worksheet.");
}
string firstSheetName = dbSchema.Rows[0]["TABLE_NAME"].ToString();
答案 2 :(得分:3)
此代码工作正常,我使用数据网格“DataGridView1”来加载工作表的所有内容
Dim MyConnection As System.Data.OleDb.OleDbConnection
Dim DtSet As System.Data.DataSet : Dim filteext As String = ""
''check for the file type
If IO.Path.GetExtension(fileName) = "xls" Then
filteext = "Excel 8.0"
ElseIf IO.Path.GetExtension(fileName) = ".xlsx" Then
filteext = "Excel 12.0"
End If
''open connection
MyConnection = New System.Data.OleDb.OleDbConnection _
("provider=Microsoft.Jet.OLEDB.4.0;Data Source='" & fileName & "';Extended Properties=" & filteext & ";")
MyConnection.Open()
Dim myTableName = MyConnection.GetSchema("Tables").Rows(0)("TABLE_NAME")
Dim MyCommand As OleDbDataAdapter = New OleDbDataAdapter(String.Format("SELECT * FROM [{0}]", myTableName), MyConnection)
MyCommand.TableMappings.Add("Table", "TestTable")
DtSet = New System.Data.DataSet
MyCommand.Fill(DtSet)
DataGridView1.DataSource = DtSet.Tables(0)
'DtSet.DataSetName.
MyConnection.Close()
答案 3 :(得分:1)
您可以使用GetOleDbSchemaTable(VB)或GetOleDbSchemaTable(C#)。
使用表枚举它将返回所有工作表名称的列表,然后您可以使用它们动态构建所需的SQL。
您可以使用:
MySchemaTable = MyConnection.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, New Object() {Nothing, Nothing, Nothing, "TABLE"})
所有工作表名称将作为DataTable的一部分返回,您可以通过它们进行迭代。
可以在
上检索使用OleDbSchemaGuid信息
- 列
- 外键
- 索引
- 主键
- 表
- 浏览
完整的MSDN文档here
答案 4 :(得分:1)
基本上是Anirudh Gaur答案的副本。我做了一些重新格式化代码并将其放入函数中。我添加了一个StringBuilder,所以我可以使用SELECT语句做更多的事情。
Upvotes转到Anirudh Gaur
Private Function Load_XLS(FileName As String) As DataTable
Dim DataTable As New DataTable
Dim Format As String = ""
If IO.Path.GetExtension(FileName) = ".xls" Then
Format = "Excel 8.0"
ElseIf IO.Path.GetExtension(FileName) = ".xlsx" Then
Format = "Excel 12.0"
End If
Using Connection As New OleDb.OleDbConnection("provider=Microsoft.Jet.OLEDB.4.0;Data Source='" & FileName & "';Extended Properties=" & Format & ";")
Connection.Open()
Dim TableName As String = Connection.GetSchema("Tables").Rows(0)("TABLE_NAME")
Dim SQLCommand As New Text.StringBuilder
SQLCommand.AppendLine("SELECT *")
SQLCommand.AppendLine("FROM [{0}]")
Dim Command As OleDb.OleDbDataAdapter = New OleDb.OleDbDataAdapter(String.Format(SQLCommand.ToString, TableName), Connection)
Command.Fill(DataTable)
Connection.Close()
End Using
Return DataTable
End Function
答案 5 :(得分:1)
这是我的解决方案▼(轻松,快速,可执行,可理解)
internal static DataTable GetExcelSheet(string excelFile,string sheetName = "")
{
string fullPathToExcel = Path.GetFullPath(excelFile);
string connString = string.Format("Provider=Microsoft.ACE.OLEDB.12.0;Data Source={0};Extended Properties='Excel " + (excelFile.ToLower().EndsWith("x") ? "12.0" : "8.0") + ";HDR=yes'", fullPathToExcel);
return GetDataTable(connString, "SELECT * FROM [" + (string.IsNullOrEmpty(sheetName) ? GetTableName(connString, 0) : sheetName + "$") + "]");
}
private static DataTable GetDataTable(string connectionString, string sql)
{
DataTable dt = new DataTable();
using (OleDbConnection conn = new OleDbConnection(connectionString))
{
conn.Open();
using (OleDbCommand cmd = new OleDbCommand(sql, conn))
{
using (OleDbDataReader rdr = cmd.ExecuteReader())
{
dt.Load(rdr);
return dt;
}
}
}
}
private static string GetTableName(string connectionString, int row = 0)
{
OleDbConnection conn = new OleDbConnection(connectionString);
try
{
conn.Open();
return conn.GetSchema("Tables").Rows[row]["TABLE_NAME"] + "";
}
catch { }
finally { conn.Close();}
return "sheet1";
}
答案 6 :(得分:0)
您也可以使用这种方法来获取工作表名称。查看评论以获取更多了解
myExcelConn.Open()
//GET DATA FROM EXCEL SHEET.
Dim str As String = String.Empty
Dim Sheets As DataTable = myExcelConn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, Nothing)
For i As Integer = 0 To Sheets.Rows.Count - 1
str += Sheets.Rows(i)("TABLE_NAME").ToString() + "," //It will return sheet1,sheet2,sheet3 according to my excel file
Next
Dim objOleDB As New OleDbCommand("SELECT *FROM [" + str.Split(",")(0) + "]", myExcelConn) //It will select sheet1
Me.Label1.Text = str.Split(",")(0).Replace("$", "")
// READ THE DATA EXTRACTED FROM THE EXCEL FILE.
Dim objBulkReader As OleDbDataReader
objBulkReader = objOleDB.ExecuteReader
Dim dt As DataTable = New DataTable
dt.Load(objBulkReader)
//FINALLY, BIND THE EXTRACTED DATA TO THE GRIDVIEW.
GridView1.DataSource = dt
GridView1.DataBind()
//If you want sheet2 data
Dim objOleDB1 As New OleDbCommand("SELECT *FROM [" + str.Split(",")(1).Split(",")(0) + "]", myExcelConn)
//If you want sheet3 data
Dim objOleDB2 As New OleDbCommand("SELECT *FROM [" + str.Split(",")(2).Split(",")(0) + "]", myExcelConn)
答案 7 :(得分:0)
您可以像这样获取工作表1名称并以这种方式使用。如果要获取其他工作表名称,则可以从0,1,2 ..
增加值。 Dim myExcelConn As OleDbConnection = _
New OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" & _
Server.MapPath(".") & "\" & FileUpload1.FileName() & _
";Extended Properties=Excel 12.0;")
Dim Sheets As DataTable = myExcelConn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, Nothing)
Sheet1 = Sheets.Rows(0)("TABLE_NAME").ToString()
Dim objOleDB As New OleDbCommand("SELECT *FROM [" + Sheet1 + "]", myExcelConn)
答案 8 :(得分:0)
那是我的解决方法
c.print("How many lines do you want in the histogram? ");
int max = c.readInt();
//declare array of the same size, catch exception if user inputs string
int[] totalSize = new int[max];
int x = 0;
int y = 0;
//store all the values in total size array.
for (int i = 0; i < max; i++) {
c.print("Type in the value for this line: ");
double num = c.readDouble();
y = (int) Math.round(num);
totalSize[i] = y;
}
//print all the values at once;
for (int i = 0; i < max; i++) {
x = 0;
y = totalSize[i];
while (x < y) {
c.print("*");
x++;
}
c.println(num);
}