Question

我有一个带有表单的HTML，如下所示：

<html>

<head>
  <script type="text/javascript" src="js/jquery-1.8.3.js"></script>
</head>

<body>
  <form action="accept-file.php" method="post" enctype="multipart/form-data" id="theform">
    Your Photo: <input id="thefile" type="file" name="photo" size="25" />
    <input type="button" name="submit" value="Submit" onclick="submitform();"/>
  </form>
</body>

<script>

  function submitform()
  {
    data = $('*').serialize();

    $.post(
      'http://localhost/banksoal/1.0.0/accept-file.php',
      data
    );
  }

</script>

</html>

和.php这样的脚本：

        <?php
  //if they DID upload a file...
  if($_FILES['photo']['name'])
  {
    print_r($_FILES['photo']);
    $message = 'default message';

    //if no errors...
    if(!$_FILES['photo']['error'])
    {
      //now is the time to modify the future file name and validate the file
      $new_file_name = 'd:\\' . '--test-- '.basename($_FILES['photo']['name']); //rename file
      if($_FILES['photo']['size'] > (1024000)) //can't be larger than 1 MB
      {
        $valid_file = false;
        $message = 'Oops!  Your file\'s size is to large.';
      }
      else
      {
        $valid_file = true;
      }

      //if the file has passed the test
      if($valid_file)
      {
        //move it to where we want it to be
        move_uploaded_file($_FILES['photo']['tmp_name'], $new_file_name);
        $message = 'Congratulations!  Your file was accepted.';
      }
    }
    //if there is an error...
    else
    {
      //set that to be the returned message
      $message = 'Ooops!  Your upload triggered the following error:  '.$_FILES['photo']['error'];
    }
  }

  var_dump($message);
?>

问题：在submitform（）函数中，在以下行的脚本标记中：

data = $('*').serialize();

为什么我得到空的结果？代码有什么问题？

谢谢

Answer 1

更改此

   data = $('*').serialize();

到

 data = $('theform').serialize();

并更改此

   <form action="accept-file.php" method="post" enctype="multipart/form-data" id="theform">

到

 <form action="accept-file.php" method="post" enctype="multipart/form-data" id="theform" name ="theform">

Answer 2

尝试如下所述：http://api.jquery.com/serialize/

$('form').submit(function() {
  console.log($(this).serialize());
  return false;
});

Answer 3

您也可以使用

echo json_encode($data);

http://php.net/manual/en/function.json-encode.php

Answer 4

你无法使用Ajax上传文件，如果你必须以类似AJAX的方式上传文件，你可以使用隐藏的iframe，设置目标属性等于iframe并获取iframe的内容以了解请求是否失败< / p>

这就是我通常为此目的所做的，创建一个隐藏的iframe，它将成为表单的目标，如下所示：

<iframe name='formTarget' src='#' style='display:none;' onload='processResult(this);'></iframe>

并且在processResult中，您可以通过以下方式获取iframe的内容：

$(results).html();

这样当iframe被加载时，它会自动触发函数通知请求完成

ajax表单数据序列化失败

4 个答案: