我提取了以下3个类别,但是想要添加“AND”谓词来缩小“标记”所在的结果范围。
NSMutableArray *questionNumberArray=[[NSMutableArray alloc] init];
// Fetch questions
NSManagedObjectContext *context = self.document.managedObjectContext;
NSFetchRequest *fetchRequest =
[[NSFetchRequest alloc] initWithEntityName:@"Questions"];
//building the predicate with selected category
NSMutableArray *parr = [NSMutableArray array];
if ([cat0str length]){
[parr addObject:[NSPredicate predicateWithFormat:@"question.category CONTAINS[c] %@",cat0str]];
}
if ([cat1str length]){
[parr addObject:[NSPredicate predicateWithFormat:@"question.category CONTAINS[c] %@",cat1str]];
}
if ([cat2str length]){
[parr addObject:[NSPredicate predicateWithFormat:@"question.category CONTAINS[c] %@",cat2str]];
}
NSPredicate *compoundPredicate = [NSCompoundPredicate orPredicateWithSubpredicates:parr];
[fetchRequest setPredicate:compoundPredicate];
NSPredicate *markPredicate =[NSPredicate predicateWithFormat:@"question.mark == 1"];
}
//我想做那样的事情:
NSPredicate *finalPredicate = [compoundPredicate && markPredicate];
[fetchRequest setPredicate:finalPredicate];
答案 0 :(得分:1)
这是你在找什么?
NSPredicate *finalPredicate = [NSCompoundPredicate andPredicateWithSubpredicates:
[NSArray arrayWithObjects:compoundPredicate, markPredicate, nil]];
或者,使用容器文字的“现代Objective-C”语法:
NSPredicate *finalPredicate = [NSCompoundPredicate andPredicateWithSubpredicates:
@[compoundPredicate, markPredicate]];