尝试使用count(*)
创建CriteriaBuilder
类型查询时,我会遇到以下别名问题。
我应该对下面的代码进行哪些更改才能获得计数?
约束:
代码示例摘要:
Class<ReqStatCumulative> entityClass = ReqStatCumulative.class;
@Override
public long getCountForAlertConfig(AlertConfig cfg) {
long count = 0L;
if (null != cfg) {
CriteriaBuilder qb = entityManager.getCriteriaBuilder();
Metamodel model = entityManager.getMetamodel();
EntityType<ReqStatCumulative> reqStatEntType_ = model.entity(entityClass);
CriteriaQuery<ReqStatCumulative> cq = qb.createQuery(entityClass);
Root<ReqStatCumulative> rootReqStatEnt = cq.from(reqStatEntType_);
Path<Long> processTimeSeconds = rootReqStatEnt.<Long> get("processTimeSeconds");
cq.where(qb.and(qb.greaterThan(processTimeSeconds, (long) cfg.getProcessTimeExceedsSec()),//
qb.lessThan(processTimeSeconds, (long) cfg.getProcessTimeExceedsSec() + 100))//
);//
findCountByCriteria(entityManager, cq, qb);
log.debug("\n\t#####Alert desc:" + cfg.getDescription());
log.debug("\n\t#####Alert count= " + count);
} else {
// Do nothing
}
return count;
}
public <T> Long findCountByCriteria(EntityManager em, CriteriaQuery<T> cqEntity, CriteriaBuilder qb) {
CriteriaBuilder builder = qb;
CriteriaQuery<Long> cqCount = builder.createQuery(Long.class);
Root<?> entityRoot = cqCount.from(cqEntity.getResultType());
cqCount.select(builder.count(entityRoot));
cqCount.where(cqEntity.getRestriction());
return em.createQuery(cqCount).getSingleResult();
}
日志:我希望generateAlias0用于所有where子句属性而不是generatedAlias1。
select count(*) from abc.domain.ReqStatCumulative as **generatedAlias0** where ( **generatedAlias1**.processTimeSeconds>5L ) and ( **generatedAlias1**.processTimeSeconds<200L )
10:48:57.169 [main] DEBUG o.h.h.i.ast.QueryTranslatorImpl - parse() - HQL: select count(*) from abc.domain.ReqStatCumulative as generatedAlias0 where ( generatedAlias1.processTimeSeconds>5L ) and ( generatedAlias1.processTimeSeconds<200L )
10:48:57.169 [main] DEBUG o.h.h.i.ast.QueryTranslatorImpl - --- HQL AST ---
\-[QUERY] Node: 'query'
+-[SELECT_FROM] Node: 'SELECT_FROM'
| +-[FROM] Node: 'from'
| | \-[RANGE] Node: 'RANGE'
| | +-[DOT] Node: '.'
| | | +-[DOT] Node: '.'
| | | | +-[IDENT] Node: 'abc'
| | | | \-[IDENT] Node: 'domain'
| | | \-[IDENT] Node: 'ReqStatCumulative'
| | \-[ALIAS] Node: '**generatedAlias0**'
| \-[SELECT] Node: 'select'
| \-[COUNT] Node: 'count'
| \-[ROW_STAR] Node: '*'
\-[WHERE] Node: 'where'
\-[AND] Node: 'and'
+-[GT] Node: '>'
| +-[DOT] Node: '.'
| | +-[IDENT] Node: '**generatedAlias1**'
| | \-[IDENT] Node: 'processTimeSeconds'
| \-[NUM_LONG] Node: '5L'
\-[LT] Node: '<'
+-[DOT] Node: '.'
| +-[IDENT] Node: '**generatedAlias1**'
| \-[IDENT] Node: 'processTimeSeconds'
\-[NUM_LONG] Node: '200L'
10:48:57.169 [main] DEBUG o.h.hql.internal.ast.ErrorCounter - throwQueryException() : no errors
10:48:57.169 [main] DEBUG o.h.h.i.antlr.HqlSqlBaseWalker - select << begin [level=1, statement=select]
10:48:57.169 [main] DEBUG o.h.h.internal.ast.tree.FromElement - FromClause{level=1} : erf.domain.ReqStatCumulative (generatedAlias0) -> reqstatcum0_
10:48:57.169 [main] ERROR o.h.hql.internal.ast.ErrorCounter - Invalid path: 'generatedAlias1.processTimeSeconds'
10:48:57.215 [main] ERROR o.h.hql.internal.ast.ErrorCounter - Invalid path: 'generatedAlias1.processTimeSeconds'
org.hibernate.hql.internal.ast.InvalidPathException: Invalid path: 'generatedAlias1.processTimeSeconds'
答案 0 :(得分:13)
您的代码失败是因为您对count和where子句使用了不同的Root
实例:第一个(按照定义顺序)生成generatedAlias1
别名,另一个生成generatedAlias0
}。您需要重构代码才能在两个地方使用相同的Root
实例:
CriteriaQuery<Long> cqCount = builder.createQuery(Long.class);
Root<ReqStatCumulative> entityRoot = cqCount.from(cqEntity.getResultType());
cqCount.select(builder.count(entityRoot));
Path<Long> processTimeSeconds = entityRoot.get("processTimeSeconds");
cqCount.where(qb.and(qb.greaterThan(processTimeSeconds, (long) cfg.getProcessTimeExceedsSec()),//
qb.lessThan(processTimeSeconds, (long) cfg.getProcessTimeExceedsSec() + 100))//
);//
return em.createQuery(cqCount).getSingleResult();
答案 1 :(得分:1)
我遇到了同样的问题,我解决了:
CriteriaQuery<Long> countCriteria = cb.createQuery(Long.class);
Root<EntityA> countRoot = countCriteria.from(cq.getResultType());
Set<Join<EntityA, ?>> joins = originalEntityRoot.getJoins();
for (Join<EntityA, ?> join : joins) {
countRoot.join(join.getAttribute().getName());
}
countCriteria.select(cb.count(countRoot));
if(finalPredicate != null)
countCriteria.where(finalPredicate);
TypedQuery<Long> queryCount = entityManager.createQuery(countCriteria);
Long count = queryCount.getSingleResult();
其中
originalEntityRoot是我使用where子句进行查询的主根。
答案 2 :(得分:0)
基于OP的问题,我一直在寻找更通用的解决方案。 并仅留下基于@Hector的示例的通用解决方案:
public class CountQueryHelper<T> {
final Class<T> typeParameterClass;
public CountQueryHelper(Class<T> typeParameterClass) {
this.typeParameterClass = typeParameterClass;
}
public CriteriaQuery<Long> getCountQuery(CriteriaQuery<T> originalQuery, EntityManager em) {
CriteriaBuilder cb = em.getCriteriaBuilder();
// create count query
CriteriaQuery<Long> countQuery = cb.createQuery(Long.class);
// start copying root/joins/restrictions from the original query
// copy roots
for (Root r : originalQuery.getRoots()) {
Root root = countQuery.from(r.getModel());
root.alias(r.getAlias());
}
// copy joins
for (Root r : originalQuery.getRoots()) {
Set<Join<T, ?>> joins = r.getJoins();
for (Join<T, ?> join : joins) {
for (Root countRoot : countQuery.getRoots()) {
try {
Join joinOnCount = countRoot.join(join.getAttribute().getName());
joinRecursive(joinOnCount, join);
} catch (IllegalArgumentException e) {
// attribute does not exist on this root
}
}
}
}
countQuery.select(cb.count(countQuery.from(this.typeParameterClass)));
// copy restrictions
if (originalQuery.getRestriction() != null) {
countQuery.where(originalQuery.getRestriction());
}
return countQuery;
}
private void joinRecursive(Join countJoins, Join<T, ?> originalJoin) {
for(Join original : originalJoin.getJoins()) {
Join<Object, Object> childJoin = countJoins.join(original.getAttribute().getName());
joinRecursive(childJoin, original);
}
}
}