我刚刚从春天开始,所以我开始在Heroku上使用SpringMVC。通过在Eclipse中选择Spring MVC模板,我得到了一个非常基本的应用程序。现在我试图修改它。
但是,如果我创建另一个.jsp
并访问Controller中给出的URL,我会得到一个404,这很清楚,因为我从未将Controller映射到.jsp
。但是我应该怎么做呢?
以下是我改变的一切(即使我不确定你是否需要它):
控制器:
@Controller
public class BookingController {
@Autowired
BookingService bookingService;
@RequestMapping("/AvailableBikes")
public String getAvailableBikes(Model model){
// TOOD: Fix Date
int availableBookings = bookingService.getAvailableBookings(Calendar.getInstance().getTime());
model.addAttribute("NumAvailableBikes", Integer.toString(availableBookings));
return "NumAvailableBikes";
}
}
实体:
@Entity
public class Booking {
@Id
@GeneratedValue
private Integer id;
// Lots of getters setters an attributes ...
}
服务:
@Service
public class BookingServiceImpl implements BookingService {
@Override
public void addBooking(Booking booking) {
// TODO Auto-generated method stub
}
@Override
public int getAvailableBookings(Date bookingDay) {
// TODO Auto-generated method stub
return 12;
}
@Override
public void removeBooking(Booking booking) {
// TODO Auto-generated method stub
}
}
booking.jsp:
<!doctype html>
<%@taglib uri="http://www.springframework.org/tags" prefix="spring"%>
<%@taglib uri="http://www.springframework.org/tags/form" prefix="form"%>
<%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>
<html>
<head>
<meta charset="utf-8">
<title>Spring MVC and Hibernate Template</title>
<meta content="IE=edge,chrome=1" http-equiv="X-UA-Compatible">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<link href="http://twitter.github.com/bootstrap/assets/css/bootstrap.css" rel="stylesheet">
<link href="http://twitter.github.com/bootstrap/assets/css/bootstrap-responsive.css" rel="stylesheet">
</head>
<body>
Test!
<h2>${NumAvailableBikes}</h2>
</body>
的web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Spring-Hibernate-Template</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/booking/*</url-pattern>
</servlet-mapping>
</web-app>
的applicationContext.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jdbc="http://www.springframework.org/schema/jdbc"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<context:annotation-config />
<context:component-scan base-package="org.stuttgart.fahrrad" />
<mvc:annotation-driven/>
<bean id="jspViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
<tx:annotation-driven />
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
<property name="dataSource" ref="dataSource"/>
</bean>
<beans profile="default">
<jdbc:embedded-database id="dataSource"/>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"/>
</property>
<property name="jpaProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop>
<prop key="hibernate.hbm2ddl.auto">create</prop>
</props>
</property>
</bean>
</beans>
<beans profile="prod">
<bean class="java.net.URI" id="dbUrl">
<constructor-arg value="#{systemEnvironment['DATABASE_URL']}"/>
</bean>
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource">
<property name="url" value="#{ 'jdbc:postgresql://' + @dbUrl.getHost() + @dbUrl.getPath() }"/>
<property name="username" value="#{ @dbUrl.getUserInfo().split(':')[0] }"/>
<property name="password" value="#{ @dbUrl.getUserInfo().split(':')[1] }"/>
</bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"/>
</property>
<property name="jpaProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
<!-- change this to 'verify' before running as a production app -->
<prop key="hibernate.hbm2ddl.auto">update</prop>
</props>
</property>
</bean>
</beans>
</beans>
答案 0 :(得分:3)
返回“NumAvailableBikes”;应该改为返回“预订”;
答案 1 :(得分:2)
首先考虑如何配置调度程序servlet。目前它映射到以下url模式:
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/booking/*</url-pattern>
</servlet-mapping>
这意味着只会映射在上下文根之后直接包含booking
目录的URL。所以像'contextroot / AvailableBikes'这样的网址永远不会被调度员接收和处理。我建议将您的网址格式更改为:
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
这种映射几乎可以捕获所有映射。它将匹配未映射到另一个servlet的所有URL。请注意:它还将使您需要设置配置以映射静态资源,如css和js文件。这在Spring文档中有解释。
完成此更改后,我认为您应该可以使用rootcontext/AvailableBikes
之类的网址点击Controller。在控制器中设置调试点以进行确认。另请注意,您不会使用包含.jsp文件的直接路径的URL,而是使用请求映射中指定的路径。您的jsp文件应该在webcontent directory/WEB-INF/jsp/NumAvailableBikes.jsp
。
为了显示@ booking.jsp
应该可用的webcontent dir/WEB-INF/jsp/booking.jsp
,必须修改控制器以返回String
预订。
@RequestMapping("/AvailableBikes")
public String getAvailableBikes(Model model){
// TOOD: Fix Date
int availableBookings = bookingService.getAvailableBookings(Calendar.getInstance().getTime());
model.addAttribute("NumAvailableBikes", Integer.toString(availableBookings));
return "booking";
}