任何人都可以帮助我, 我的大脑堆叠使这个集合mapreduce, 我如何获得PurchaseAmount,PurchaseReturnAmount和TotalAmount,键“年”。</ strong>
{
"_id" : {
"OwnerId" : "coba@aja.com",
"SupplierId" : BinData(3,"AYC8In8bFkGYNx34poQLlg=="),
"GroupId" : BinData(3,"mzWBCilngEGd72YpeyijcQ=="),
"ProductId" : BinData(3,"gZ2g/syue06v8b88+0pqRA=="),
"Date" : ISODate("2013-01-15T00:00:00Z")
},
"value" : {
"OwnerId" : "oetawan@dokuku.com",
"Date" : ISODate("2013-01-15T00:00:00Z"),
"SupplierId" : BinData(3,"AYC8In8bFkGYNx34poQLlg=="),
"SupplierName" : "Matahari",
"GroupId" : BinData(3,"mzWBCilngEGd72YpeyijcQ=="),
"GroupCode" : "Umum",
"GroupName" : "Umum",
"ProductId" : BinData(3,"gZ2g/syue06v8b88+0pqRA=="),
"ProductCode" : null,
"ProductBarcode" : "IPAD2",
"ProductName" : "iPad 2",
"PurchaseAmount" : 19500000,
"PurchaseReturnAmount" : 0,
"TotalAmount" : 19500000
}
} 我想使用这个地图reduce to C#
答案 0 :(得分:0)
这是使用MR的shell示例。当然,您也可以使用聚合框架来完成它,但可能您希望在后台运行它;
db.so.mapReduce(
function () { /* map */
var key = this._id.Date.getFullYear();
emit(key, { PurchaseAmount:this.value.PurchaseAmount, PurchaseReturnAmount:this.value.PurchaseReturnAmount, TotalAmount:this.value.TotalAmount } );
},
function (key, array) { /* reduce*/
var result = { PurchaseAmount: 0, PurchaseReturnAmount: 0, TotalAmount: 0 };
for (var i = 0; i < array.length; i++) {
{
result.PurchaseAmount += array[i].PurchaseAmount;
result.PurchaseReturnAmount += array[i].PurchaseReturnAmount;
result.TotalAmount += array[i].TotalAmount;
}
}
return result;
},
{
out: "so_mr_example",
query:{}
}
);
db.so_mr_example.find();
产生类似的东西;
{ "_id" : 2013, "value" : { "PurchaseAmount" : 39000000, "PurchaseReturnAmount" : 0, "TotalAmount" : 39000000 } }
{ "_id" : 2014, "value" : { "PurchaseAmount" : 19500000, "PurchaseReturnAmount" : 0, "TotalAmount" : 19500000 } }