我不知道为什么但是无论何时你或者电脑在我的游戏中受到重创，网格都会得到更新。 播放器和计算机网格是' - '字符的多维数组，当你得到一个命中时它变为'x'。在游戏循环中，他们是一个玩家网格和计算机网格，我在不同时间单独更新它们，但是当它们被打印时它们都是相同的。有人可以帮忙吗？对不起，我是编程新手
public class Game{
public static void main(String[] args){
Grid grid = new Grid();
Computer computer = new Computer();
Player player = new Player();
String playerGuess;
player.setPlayerShips();
computer.setComputerShips();
char[][] playerGrid= Grid.gridArray;
char[][] computerGrid = Grid.gridArray;
System.out.println("Welcome to BATTLESHIP");
System.out.println("You are to sink your opponents 3 ships, each 3 units in length.");
System.out.println("The ships can be both vertical and horizontal.");
System.out.println("Enter your coordinate guess in the form A1, B5, F6, etc.");
System.out.println("Since the grid is 7x7, coordinates go from A1-G7.");
System.out.println("Letters are vertical, numbers are horizontal.");
System.out.println("You will also have 3 ships placed randomly, which the computer will also try to guess.");
System.out.println("During the game, enter exit if you would like to quit.");
System.out.println();
while(true){
System.out.println("Your Grid");
grid.printGrid(playerGrid);
System.out.println("Opponent's Grid");
grid.printGrid(computerGrid);
System.out.println();
playerGuess=player.getGuess();
if(playerGuess.equals("exit")){
break;
}else{
playerGuess=grid.convert(playerGuess);
}
player.setFirstCo(playerGuess);
player.setSecondCo(playerGuess);
System.out.println();
if(player.isHit(player.firstCo, player.secondCo)){
player.addHits(player.firstCo, player.secondCo);
System.out.println("Hit!");
System.out.println();
computerGrid=Grid.newGrid(computerGrid,player.firstCo,player.secondCo);
}else{
System.out.println("Miss.");
System.out.println();
}
if(player.hasWon()){
System.out.println("Congratulations, you have sunk all your opponents ships!");
break;
}
computer.guess=computer.getGuess();
computer.lastGuess=computer.guess;
if(computer.isHit(computer.guess[0],computer.guess[1])){
computer.addHits(computer.guess[0],computer.guess[1]);
System.out.println("Computer has hit!");
System.out.println();
playerGrid=grid.newGrid(playerGrid, computer.guess[0], computer.guess[1]);
if(computer.hasWon()){
System.out.println("Computer has sunk all your ships! You lose.");
break;
}
}else{
System.out.println("Computer has missed.");
System.out.println();
}
}
}
}
我得到了单独打印的网格，但我的地方船方法有问题。有人可以看看吗？假设选择随机的x，y坐标（每艘船3个点）并为3艘船做这个。它有时连续放4个点而没有其他船只（我认为船只只是重叠，但我试图修复）。无论如何，如果你能提供帮助，请提前谢谢。
//set player ships coordinates, can be numbers from 0-6
public static void setPlayerShips(){
int randX, randY;
int direction; //will be random int 0-1, determines direction ship will extend(up/down, left/right)
randX=(int)(Math.random()*7);
randY=(int)(Math.random()*7);
direction=(int)(Math.random()*2);
playerShip1[0]=randX;
playerShip1[1]=randY;
if(direction==0){//extend upwards or downwards 2 units(y values change, x stays the same)
playerShip1[2]=randX;
playerShip1[4]=randX;
if(randY>3){//if y value is greater than 3, has to extend down or it wont fit
playerShip1[3]=randY-1;
playerShip1[5]=randY-2;
}else if(randY<2){//if y value is less than 2, has to extend up or it wont fit
playerShip1[3]=randY+1;
playerShip1[5]=randY+2;
}else{//if direction doesnt matter, just extend upwards
playerShip1[3]=randY+1;
playerShip1[5]=randY+2;
}
}else if(direction==1){//extends left or right 2 units(y values stay the same, x changes)
playerShip1[3]=randY;
playerShip1[5]=randY;
if(randX>3){//if x is greater than 3, must extend left or it wont fit
playerShip1[2]=randX-1;
playerShip1[4]=randX-2;
}else if(randX<2){//if x is less than 2, must extend right or it wont fit
playerShip1[2]=randX+1;
playerShip1[4]=randX+2;
}else{//if direction doesnt matter, just extend right
playerShip1[2]=randX+1;
playerShip1[4]=randX+2;
}
}
//do same for both other ships, do quick checks to make sure original coordinates arent the same
do{
randX=(int)(Math.random()*7);
randY=(int)(Math.random()*7);
}while(randX==playerShip1[0] && randY==playerShip1[1]);
direction=(int)(Math.random()*2);
playerShip2[0]=randX;
playerShip2[1]=randY;
if(direction==0){
playerShip2[2]=randX;
playerShip2[4]=randX;
if(randY>3){
playerShip2[3]=randY-1;
playerShip2[5]=randY-2;
}else if(randY<2){
playerShip2[3]=randY+1;
playerShip2[5]=randY+2;
}else{
playerShip2[3]=randY+1;
playerShip2[5]=randY+2;
}
}else if(direction==1){
playerShip2[3]=randY;
playerShip2[5]=randY;
if(randX>3){
playerShip2[2]=randX-1;
playerShip2[4]=randX-2;
}else if(randX<2){
playerShip2[2]=randX+1;
playerShip2[4]=randX+2;
}else{
playerShip2[2]=randX+1;
playerShip2[4]=randX+2;
}
}
do{
randX=(int)(Math.random()*7);
randY=(int)(Math.random()*7);
}while((randX==playerShip1[0]&& randY==playerShip1[1])&&(randX==playerShip2[0] && randY==playerShip2[1]));
direction=(int)(Math.random()*2);
playerShip3[0]=randX;
playerShip3[1]=randY;
if(direction==0){
playerShip3[2]=randX;
playerShip3[4]=randX;
if(randY>3){
playerShip3[3]=randY-1;
playerShip3[5]=randY-2;
}else if(randY<2){
playerShip3[3]=randY+1;
playerShip3[5]=randY+2;
}else{
playerShip3[3]=randY+1;
playerShip3[5]=randY+2;
}
}else if(direction==1){
playerShip3[3]=randY;
playerShip3[5]=randY;
if(randX>3){
playerShip3[2]=randX-1;
playerShip3[4]=randX-2;
}else if(randX<2){
playerShip3[2]=randX+1;
playerShip3[4]=randX+2;
}else{
playerShip3[2]=randX+1;
playerShip3[4]=randX+2;
}
}
}
答案 0 :(得分：2)
这是问题所在：
char[][] playerGrid= Grid.gridArray;
char[][] computerGrid = Grid.gridArray;
你只有实际上在这里获得了一个char[][]对象。两个变量都引用同一个对象......通过这两个变量可以看到对该对象所做的任何更新。
看起来就像Grid.gridArray实际上是一个静态变量，这是另一个问题。您几乎肯定希望将其设为实例变量...然后创建两个实例Grid而不只是一个。
基本上，我会退后一步，弄清楚Grid的一个实例是什么意思。你真的需要公开gridArray变量吗？为什么网格不能自行打印？