当值超过150时，Int值不相等？

Question

代码看起来像

public void option() {
    seeTasks = tasks.getTasks();
        for (int i = 0; i < seeTasks.size(); i++) {
            for (int b = 0; b < seeBoxes.size(); b++) {
               System.out.println("see Tasks: " + seeTasks.get(i) + 
                           " see Boxes " + seeBoxes.get(b));
            if(seeTasks.get(i) == seeBoxes.get(b)) {
                option.add(seeTasks.get(i));
            }
        }
    }
    System.out.println(option);
}

如果if的值低于150，则seeTaks.get(i) seeTasks.get(i)语句将不会通过。这怎么可能？如下所示，370不包括在内。如果我将110更改为150，则不会通过。

println的输出是：

see Tasks: 50 see Boxes 50
see Tasks: 50 see Boxes 110
see Tasks: 50 see Boxes 150
see Tasks: 50 see Boxes 210
see Tasks: 50 see Boxes 270
see Tasks: 50 see Boxes 310
see Tasks: 50 see Boxes 370
see Tasks: 50 see Boxes 430
see Tasks: 110 see Boxes 50 
see Tasks: 110 see Boxes 110
see Tasks: 110 see Boxes 150
see Tasks: 110 see Boxes 210
see Tasks: 110 see Boxes 270
see Tasks: 110 see Boxes 310
see Tasks: 110 see Boxes 370
see Tasks: 110 see Boxes 430
see Tasks: 370 see Boxes 50
see Tasks: 370 see Boxes 110
see Tasks: 370 see Boxes 150
see Tasks: 370 see Boxes 210
see Tasks: 370 see Boxes 270
see Tasks: 370 see Boxes 310
see Tasks: 370 see Boxes 370
see Tasks: 370 see Boxes 430
[50, 110]

Answer 1

我怀疑

seeTasks.get(i)

和

seeBoxes.get(b)

都返回Integer。然后，对于低于128的值，Integer高速缓存返回相同的实例，但对于较大的值，则返回新实例。使用equals()。