Question

我为表提供了一个包含不同发布者记录的表，每条记录都在时间戳类型的列中有一个日期。

id | id_publisher | date
1           1      11/2012 03:09:40 p.m.
2           1      12/2012 03:09:40 p.m.
3           2      01/2013 03:09:40 p.m.
4           3      01/2013 03:09:40 p.m.
5           4      11/2012 03:09:40 p.m.
6           4      02/2013 03:09:40 p.m.
7           4      02/2012 03:09:40 p.m.

我需要计算每个发布商每个月发布的记录数量。例如

Month    |  id_publisher         | num
11/2012  |          1            |   1
11/2012  |          2            |   0
11/2012  |          3            |   0
11/2012  |          4            |   1
.....
02/2013  |          4            |   2

我试过了从raw_occurrence_record group by month（date）中选择count（id），id_publisher;

但是，不要工作。

Answer 1

假设您的日期是实际的datetime列：

SELECT MONTH(date), YEAR(date), id_publisher, COUNT(*)
FROM raw_occurrence_record
GROUP BY MONTH(date), YEAR(date), id_publisher

您可以连接您的月份＆amp;一年如此：

SELECT CONCAT(MONTH(date), '/', YEAR(date)) AS Month, id_publisher, COUNT(*)
FROM raw_occurrence_record
GROUP BY MONTH(date), YEAR(date), id_publisher

要查找没有记录的月份，您需要一个日期表。如果你不能创建一个，你可以UNION ALL这样的日历表：

SELECT a.year, a.month, b.id_publisher, COUNT(b.id_publisher) AS num
FROM
  (SELECT 11 AS month, 2012 AS year
   UNION ALL
   SELECT 12, 2012
   UNION ALL
   SELECT 1, 2013
   UNION ALL
   SELECT 2, 2013) a
LEFT JOIN raw_occurence_record b
  ON YEAR(b.date) = a.year AND MONTH(b.date) = a.month
GROUP BY a.year, a.month, b.id_publisher

带有count和group by的MySQL Query

1 个答案:

See a demo