我有一个用户反馈的表单视图:
urls.py:
url(
r'^feedback/$',
'tool.views.Feedback',
name='feedback'
),
url(
r'^thanks/$',
direct_to_template, {
'template': 'tool_feedback_thanks.html'
},
name='feedback_thanks'
),
forms.py:
class FeedbackForm(forms.Form):
yes_no = forms.ChoiceField(
choices=YES_NO_CHOICE,
initial=1,
widget=forms.RadioSelect(attrs={'class': 'can_reveal_input'}),
label="Are you happy with Our service?"
)
comments = forms.CharField(
widget=forms.Textarea(attrs={
'class': 'hidden', 'placeholder': 'Leave us your comments...'
}),
required=False,
label=""
)
views.py:
def Feedback(request,
template_name='tool_feedback.html'):
title = u'Leave us some feedback'
form = FeedbackForm(request.POST or None)
if form.is_valid():
yes_no = form.cleaned_data['yes_no']
comments = form.cleaned_data['comments']
sender = "A Unirac website user"
recipients = ['person@example.com']
send_mail(yes_no, comments, sender, recipients)
return HttpResponseRedirect(
reverse('feedback_thanks')
)
return render_to_response(template_name, {
'title': title,
'form': form,
}, RequestContext(request))
这是一种享受,但现在客户要求每个页面都包含此表单。我想表格可以通过js提交到相应的网址,但是在每个页面上包含未绑定表单的最佳方式是什么?
非常感谢任何帮助。
答案 0 :(得分:4)
我认为包含表单的最简单方法是使用assignment_tag:
在模板库中:
@register.assignment_tag
def feedback_form(format_string):
return FeedbackForm()
在模板中
{% feedback_form as form %}
{# display form... %}
{{ form.as_p }}
答案 1 :(得分:0)
要添加到@bmihelac,谁的答案对我来说真的很有效。由于django 2.0 assignment_tag
被deprecated赞成simple_tag
。因此,您可以将assignment_tag
替换为simple_tag
,从而完全按照他的回答,如下所示:
from django import template
from .forms import FeedbackForm
register = template.Library()
@register.simple_tag
def feedback_form():
return FeedbackForm()
然后只需参考https://docs.djangoproject.com/en/2.1/howto/custom-template-tags/#code-layout,了解有关如何将其导入模板的信息!