Android手机中服务器的HTTP响应状态代码打印在响应正文中

Question

我正在使用http://hc.apache.org/httpcomponents-core-ga/httpcore/examples/org/apache/http/examples/ElementalHttpServer.java for Android。

我使用以下代码设置响应：

HttpResponse getResponse = new BasicHttpResponse(HttpVersion.HTTP_1_1, 404, "Not Found");
getResponse.setEntity(new StringEntity(new String("The requested resource " + target + " could not be found due to mismatch!!")));  
conn.sendResponseHeader(getResponse);
conn.sendResponseEntity(getResponse);

我在Mozilla Poster或浏览器中的回复标题为404，响应正文为：

The requested resource  could not be found due to mismatch!!HTTP/1.1 200 OK

如何只获取HTTP正文字符串？为什么我得到HTTP / 1.1 200 OK作为回应。我不在我的代码中设置它。任何帮助表示赞赏。

Answer 1

使用ResponseHandler。一行代码。有关使用它的示例Android项目，请参阅here和here。

public void postData() {
    // Create a new HttpClient and Post Header
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://www.yoursite.com/user");

    try {
        // Add your data
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("id", "12345"));
        nameValuePairs.add(new BasicNameValuePair("stringdata", "AndDev is Cool!"));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Execute HTTP Post Request
        ResponseHandler<String> responseHandler=new BasicResponseHandler();
        String responseBody = httpclient.execute(httppost, responseHandler);
        JSONObject response=new JSONObject(responseBody);
    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    } catch (IOException e) {
        // TODO Auto-generated catch block
    }
} 

在 - http://www.androidsnippets.org/snippets/36/

添加此帖子和完整HttpClient的组合

Answer 2

这可能对你有所帮助......  我认为response是您需要的

HttpClient client = new DefaultHttpClient();

        HttpResponse httpResponse;

        try {
            httpResponse = client.execute(request);
            responseCode = httpResponse.getStatusLine().getStatusCode();
            message = httpResponse.getStatusLine().getReasonPhrase();

            HttpEntity entity = httpResponse.getEntity();

            if (entity != null) {

                InputStream instream = entity.getContent();
                response = convertStreamToString(instream);

                // Closing the input stream will trigger connection release
                instream.close();
            }

        } catch (ClientProtocolException e) {
            client.getConnectionManager().shutdown();
            e.printStackTrace();
        } catch (IOException e) {
            client.getConnectionManager().shutdown();
            e.printStackTrace();
        }

Answer 3

我定义的handle（）方法存在问题。我正在为每个请求创建一个新的HttpResponse，而不是使用

中传递的响应

public void handle(HttpRequest request, HttpResponse response, HttpContext context)