Question

我是android的新手我使用edittext搜索在我的android中搜索工作正常，搜索代码如下：

inputSearch.addTextChangedListener(new TextWatcher() {

    @Override
    public void onTextChanged(CharSequence s, int start,
            int before, int count) {
        // TODO Auto-generated method stub
        // When user changed the Text
        arrayAdapter.getFilter().filter(s);
        arrayAdapter.notifyDataSetChanged();
    }
    ..........
}}

我使用simpleadapter在listview中显示有两个colomn col1，col2的数据说：

arrayAdapter = new SimpleAdapter(LabelUser.this, mylistData,
                        R.layout.two_col_row, columnTags, columnIds);
list.setAdapter(arrayAdapter);

单击列表

：

list.setOnItemClickListener(new OnItemClickListener() {
    @Override
    public void onItemClick(AdapterView<?> arg0, View v,
            int position, long id) {
        // TODO Auto-generated method stub

        String selectedFromList = (list.getItemAtPosition(position).toString());

        System.out.println(selectedFromList);
        startActivity(new Intent("com.example.mysampleapp.DASHBOARDTAB"));

    }
});

并输出为：

{col1=A K JOHN, col2=21.45}

我的问题是如何从上面获取字符串，即col1

示例var =“A K JOHN”

listview创建：

final ListView list = (ListView) findViewById(R.id.listView1);
                ArrayList<HashMap<String, String>> mylistData = new ArrayList<HashMap<String, String>>();

                String[] columnTags = new String[] { "col1", "col2" };
                int[] columnIds = new int[] { R.id.column1, R.id.column2 };
                for (int i = 0; i < labelIdArray.length; i++) {
                    HashMap<String, String> map = new HashMap<String, String>();
                    map.put("col1", labelArray[i]);
                    map.put("col2", labelRateArray[i]);
                    mylistData.add(map);
                    list.setAdapter(arrayAdapter);
                }

Answer 1

如果你想获取第一列的值，我认为以下代码可以正常工作，

   String selectedFromList = columnTags[position];

试着试着告诉它是否有用。

从可搜索的多列列表视图中获取字符串

1 个答案: