Question

表格结构帐单

CREATE TABLE IF NOT EXISTS `bill` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `agent_id` int(11) NOT NULL,
  `date` date NOT NULL,
  `amount` int(100) NOT NULL,
  `cheque` int(11) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=21 ;

--
-- Dumping data for table `bill`
--

INSERT INTO `bill` (`id`, `agent_id`, `date`, `amount`, `cheque`) VALUES
(1, 1, '2013-01-01', 10, 15),
(2, 1, '2013-01-01', 10, 0),
(3, 2, '2013-01-02', 10, 0),
(4, 1, '2013-01-03', 12, 0),
(5, 3, '2013-01-04', 100, 0),
(6, 2, '2013-01-05', 14, 0),
(7, 5, '2013-01-05', 18, 0),
(8, 7, '2013-01-05', 22, 0),
(9, 6, '2013-01-04', 19, 0),
(10, 6, '2013-01-06', 20, 0),
(11, 5, '2013-01-07', 21, 0),
(12, 6, '2013-01-08', 11, 0),
(13, 7, '2013-02-09', 19, 0),
(14, 6, '2013-01-10', 150, 0),
(15, 1, '2012-12-31', 100, 0),
(16, 1, '2012-01-11', 500, 20),
(17, 1, '2013-02-01', 210, 0),
(18, 1, '2013-02-18', 100, 0),
(19, 6, '2013-01-31', 100, 0),
(20, 3, '2013-01-11', 250, 50);

表格结构bill_agents

CREATE TABLE IF NOT EXISTS `bill_agents` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` varchar(11) NOT NULL,
  `target` int(11) NOT NULL,
  `join_date` date NOT NULL,
  `resign_date` date NOT NULL,
  `hide` int(11) NOT NULL DEFAULT '0',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ;

--
-- Dumping data for table `bill_agents`
--

INSERT INTO `bill_agents` (`id`, `name`, `target`, `join_date`, `resign_date`, `hide`) VALUES
(1, 'Agent 1', 10, '2013-01-01', '0000-00-00', 0),
(2, 'Agent 2', 5000, '2013-01-01', '0000-00-00', 0),
(3, 'Agent 3', 5000, '2013-01-01', '0000-00-00', 0),
(4, 'Agent 4', 5000, '2013-01-03', '2013-01-06', 0),
(5, 'Agent 5', 5000, '2013-01-01', '0000-00-00', 0),
(6, 'Agent 6', 5000, '2013-01-02', '0000-00-00', 0),
(7, 'Agent 7', 5000, '2013-01-02', '0000-00-00', 1);

我当前的结果：

（1-31是日期），代码为

<table width="100%" border="1" cellspacing="4" cellpadding="1">
  <tr>
    <td>&nbsp;</td>
     <?php
for ($i=01; $i<=31; $i++)
  {?>
    <td><?php echo $i; ?></td>
    <?php

  }
?>
    <td>Total</td>
  </tr>
  <?php 
    $query4 = "SELECT DISTINCT bill.agent_id, bill.date, SUM(bill.amount + bill.cheque) AS total, bill_agents.id,bill_agents.name ".
        "FROM bill, bill_agents ".
        "WHERE bill.agent_id = bill_agents.id AND YEAR(date)  = YEAR(CURDATE()) AND MONTH(date) = MONTH(CURDATE()) ".
        "GROUP BY bill.agent_id , DATE(bill.date)   ".
        "ORDER BY bill.date ASC ";
     $result4 = mysql_query($query4) or die('Error, query failed1'); 
    if  (mysql_num_rows($result4)>0){
    mysql_data_seek($result4, 0);   

?>
  <?php $total_1 = 0;  while($row4 = mysql_fetch_array($result4, MYSQL_ASSOC)){?>
  <?php $date =    $row4['date'];

    $var = $date;
    $date = date("d-m-Y", strtotime($var) );
    $date=substr($date, 0, -8); 

    echo $date;

    ?>
  <tr>
    <td><?php echo $row4['name']; ?></td>
    <?php
for ($i=01; $i<=31; $i++)
  {?>
    <td><?php if ($date == $i) echo $row4['total']; ?></td>
    <?php

  }
?>
    <td></td>
  </tr>
  <?php } } ?>
  <tr>
    <td colspan="31"></td>
    <td>Total</td>
    <td></td>
  </tr>
</table>

我想要创建的是我不想复制代理名称如果数据库中的多个条目应该只在当前日期之下，那么总计也应该是。怎么可能sql查询？或者我是否需要使用其他代码创建？

以下是我尝试创建

的示例

Answer 1

$select_agent_id = mysql_query("select agent_id from bill group by agent_id");
while ($fetch = mysql_fetch_array($select_agent_id)) {
    $agent_id[] = $fetch['agent_id'];
}
$number_of_agents = count($agent_id);

    $output = "<table border='2px' bordercolor='#460000'>";
    $output .="<tr>";
    $output .="<td>Name</td>";
    for($i=1; $i<=31; $i++) {
        $output .="<td>".$i."</td>";
    }
    $output .="<td>Total</td>"; 
    $output .="</tr>";

foreach($agent_id as $id) {

    $select_records = mysql_query("select *, sum(amount) from bill where agent_id = $id 
                      and date between '2013-01-01' and '2013-01-31' group by date");

    $select_agent_name = mysql_query("select name from bill_agents where id=$id");
    $fetch_name = mysql_fetch_array($select_agent_name);
    $agent_name = $fetch_name['name'];


    $rows_count = mysql_num_rows($select_records);
    while($fetch_dates = mysql_fetch_array($select_records)) {
        $dates[] =substr($fetch_dates['date'],-2,2);
        $amounts[] = $fetch_dates['sum(amount)'];
    }
    $output .= "<tr>";
    $output .="<td>".$agent_name."</td>";

    for($i=1;$i<=31;$i++) {

        if(!empty($dates)) {

            if($i==$dates[0]) {
                $output .="<td>".$amounts[0]."</td>";
                array_shift($amounts);
                array_shift($dates);
            } else {
                $output .= "<td>&nbsp;</td>";
            }
        } else {
            $output .= "<td>&nbsp;</td>";
        }

    }
    $total_amount_query = mysql_query("select sum(amount) from bill where agent_id = $id 
                      and date between '2013-01-01' and '2013-01-31' group by agent_id");
    $fetch_total_amount = mysql_fetch_array($total_amount_query);
    $output .="<td>".$fetch_total_amount['sum(amount)']."</td>";                  
    $output .= "</tr>";

}
$output .="</table>";
echo $output;

@Preethu Alex：上面是你的代码。请检查并让我知道。希望这可以帮助。我没有检查 SQL INJECTION 。我还在查询中给出了一些静态日期。请按照修改

进行修改

如何在不重复代理名称的情况下创建PHP Mysql日报？

1 个答案: