Question

我正在使用ajax联系表单，但它似乎无法正常工作。一旦我尝试提交表单，我就会收到“请填写所有字段”的消息，即使我已将它们全部填满。

这是我目前的表单代码：

    <form method="get" action="mail.php">

    <input name="fname" type="text" value="Enter your First Name here..." id="fname" onfocus="if(this.value == 'Enter your First Name here...') this.value = ''"/>
    <input name="lname" type="text" value="Enter your Last Name here..." id="lname" onfocus="if(this.value == 'Enter your Last Name here...') this.value = ''"/>
    <input name="cname" type="text" value="Enter your Company Name here..." id="cname" onfocus="if(this.value == 'Enter your Company Name here...') this.value = ''"/>
    <input name="web" type="text" value="Enter your Website here..." id="web" onfocus="if(this.value == 'Enter your Website here...') this.value = ''"/>
    <input name="email" type="text" value="Enter your E-mail here..." id="email" onfocus="if(this.value == 'Enter your E-mail here...') this.value = ''"/>
    <input name="phone" type="text" value="Enter your Phone Number here..." id="phone" onfocus="if(this.value == 'Enter your Phone Number here...') this.value = ''"/>
    <textarea name="message" id="message" onfocus="if(this.value == 'Enter your message here...') this.value = ''" rows="" cols="">Enter your message here...</textarea>
    <input name="submit" type="submit" value="Submit" id="submit"/>
    <div id="response" style="float:right">
    <p></p>
    </div>

    </form>

我的mail.php的内容：

    <?php

    if ($_GET['fname'] == "" || $_GET['lname'] == "" || $_GET['cname'] == "" || $_GET['web'] == "" || $_GET['phone'] == "" ||  $_GET['email'] == "" || $_GET['message'] == "") {
        echo 'Please fill in all fields!';
        exit;
    }

    if (strlen($_GET['fname']) < 3) {
        echo 'Your name should be atleast 3 characters long!';
        exit;
    }

    if (strlen($_GET['lname']) < 3) {
        echo 'Your name should be atleast 3 characters long!';
        exit;
    }

    if (strlen($_GET['cname']) < 3) {
        echo 'Your name should be atleast 3 characters long!';
        exit;
    }

    if (strlen($_GET['web']) < 3) {
        echo 'Your name should be atleast 3 characters long!';
        exit;
    }

    if (strlen($_GET['phone']) < 3) {
        echo 'Your name should be atleast 3 characters long!';
        exit;
    }

    if (!preg_match("/^([a-zA-Z0-9])+([\.a-zA-Z0-9_-])*@([a-zA-Z0-9_-])+(\.[a-zA-Z0-9_-]+)*\.([a-zA-Z]{2,6})$/", $_GET['email'])) {
        echo 'Please enter a valid email address!'; 
        exit;
    }

    if (strlen($_GET['message']) < 10) {
        echo 'Your message should be atleast 10 characters long!';
        exit;
    }

    $to = 'my@email.com';

    $name = stripslashes($_GET['name']);
    $email = stripslashes($_GET['email']);

    $subject  = "Contact request";
    $msg  = "From:".$name."\r\n";
    $msg .= "e-Mail:".$email."\r\n";
    $msg .= "Subject:".$subject."\r\n\n";
    $msg .= "---Message--- \r\n".nl2br(stripslashes($_GET['message']))."\r\n\n";

    $mail = mail($to, $subject, $msg, "From:".$email);

    if($mail) {
        echo 'We will be in touch shortly!';
    } else {
        echo 'Error: Message could not be sent!';
    }

    ?>

最后但并非最不重要的是ajax.js

     $(function() {
        $("input#submit").click( 
            function() {
                $('#response p').empty().append("<img src='img/ajax-loader.gif' />");

                var fname = $("#fname").val();  
                var lname = $("#lname").val();
                var cname = $("#cname").val(); 
                var web = $("#web").val();  
                var email = $("#email").val(); 
                var phone = $("#phone").val(); 
                var message = $("#message").val(); 

                var dataString = 'fname='+ fname + 'lname='+ lname + 'cname='+ cname + 'web='+ web + '&email=' + email + 'phone='+ phone + '&message=' + message;  

                $.ajax({

                    url: "mail.php",
                    data: dataString,
                    type: "GET",
                    success: function(responseText) {

                         $('#response p').empty().append(responseText);
                         }
                     });

            return false;

        });
      });

知道这里有什么问题吗？一些专家建议真的很有帮助。

Answer 1

在构建&

时，您可能需要在dataString前添加每个参数

var dataString = 'fname='+ fname + '&lname='+ lname + '&cname='+ cname + '&web='+ web + '&email=' + email + '&phone='+ phone + '&message=' + message;

在您的代码中，您仅针对email和message执行此操作。

Ajax联系表单无法正常工作

1 个答案: