Question

我尝试使用str_replace将双字母语言缩写转换为完整字词。我遇到的问题是他们在回声时会相互影响。

$lang = str_replace("en", "English", $lang); 
$lang = str_replace("es", "Spanish", $lang);
$lang = str_replace("pt", "Portuguese", $lang); 
$lang = str_replace("fr", "French", $lang);
$lang = str_replace("de", "German", $lang);
$lang = str_replace("it", "Italian", $lang);
$lang = str_replace("pl", "Polish", $lang);
$lang = str_replace("ru", "Russian", $lang);
$lang = str_replace("sv", "Spanish (El Salvador)", $lang);
$lang = str_replace("ko", "Korean", $lang);
$lang = str_replace("zh", "Chinese", $lang);
$lang = str_replace("nl", "Dutch", $lang);

一个例子：当我回复en时，我得到EnglIcelandich。

上面的列表更大，但这只是一个例子。我曾尝试重命名变种，但没有运气。

Answer 1

很简单！请改用strtr。

<?php
$replace = array(
    "en" => "English",
    "es" => "Spanish",
    "pt" => "Portuguese",
    "fr" => "French",
    "de" => "German",
    "it" => "Italian",
    "pl" => "Polish",
    "ru" => "Russian",
    "sv" => "Spanish (El Salvador)",
    "ko" => "Korean",
    "zh" => "Chinese",
    "nl" => "Dutch"
);

echo strtr("en it sv\n", $replace);

Answer 2

您可以使用preg_replace_callback：

一次完成所有操作

$map = array(
    'en' => 'English',
    ...
);

$lang = preg_replace_callback('/' . implode('|', array_keys($map)) . '/', function($match) use ($map) {
    return $map[$match[0]];
}, $lang);

哦，如果你的任何字符串中都有任何特殊字符，你需要将preg_quote映射到数组的键并将分隔符作为第二个参数传递。

Answer 3

如果$lang总是两个字符的字符串，则根本不需要搜索/替换，只需使用这样的查找表：

$languages = array(
    'en'=>'English' 
    'es'=>'Spanish'
    'pt'=>'Portuguese' 
    'fr'=>'French'
    'de'=>'German'
    'it'=>'Italian'
    'pl'=>'Polish'
    'ru'=>'Russian'
    'sv'=>'Spanish (El Salvador)'
    'ko'=>'Korean'
    'zh'=>'Chinese'
    'nl'=>'Dutch'   
);
$lang = $languages[strtolower($lang)];

Answer 4

除非您将ensppt之类的内容视为原始值，否则只需使用模拟查找表：

$lang_lookup = array(
  'en' => 'English',
  'es' => 'Spanish',
  'pt' => 'Portuguese',
  // ...
);
$lang = array_key_exists($lang, $lang_lookup) ? $lang_lookup[$lang] : 'Unknown';

或者（但速度较慢）你可以将一个字符串复制到另一个字符串：

$lang_lookup = array(
  'en'=>'English',
  'es'=>'Spanish',
  'pt'=>'Portuguese', 
  'fr'=>'French',
  'de'=>'German',
  'it'=>'Italian',
  'pl'=>'Polish',
  'ru'=>'Russian',
  'sv'=>'Spanish (El Salvador)',
  'ko'=>'Korean',
  'zh'=>'Chinese',
  'nl'=>'Dutch'   
);
$lang = 'es stands for Spanish';

$output = '';
for ($i = 0; $i < strlen($lang); $i++){
  $l = substr($lang, $i, 2);
  if (array_key_exists($l, $lang_lookup)){
    $output .= $lang_lookup[$l];
    $i++;
  } else {
    $output .= $lang[$i];
  }
}
echo $output; // "Spanish stands for Spanish"

Answer 5

如果字符串中只支持一次出现，那么只需先检查哪一个存在。使用数组作为查找表。

$languages = array(
    'en'=>'English' 
    'es'=>'Spanish'
    'pt'=>'Portuguese' 
    'fr'=>'French'
    'de'=>'German'
    'it'=>'Italian'
    'pl'=>'Polish'
    'ru'=>'Russian'
    'sv'=>'Spanish (El Salvador)'
    'ko'=>'Korean'
    'zh'=>'Chinese'
    'nl'=>'Dutch'   
);

foreach($languages as $key=>$value)
{
    if(strpos($lang,$key) !== false)
    {
        $lang = str_replace($key,$value,$lang);
        break;
    }
}

Answer 6

$entries = array(
    "en" => "English",
    "es" => "Spanish",
    "pt" => "Portuguese",
    "fr" => "French",
    "de" => "German",
    "it" => "Italian",
    "pl" => "Polish",
    "ru" => "Russian",
    "sv" => "Spanish (El Salvador)",
    "ko" => "Korean",
    "zh" => "Chinese",
    "nl" => "Dutch"
);

使用str_replace：

for ( $i = 0 ;  $i < $entries['count']; $i++ ) {
    foreach($entries[$i] as $key => $entrie) {
        if ( is_string($key) ) {
        $result = str_replace('{'.$key.'}', $entrie[0], $result);
        }
    }

    $contact_data[] = $result;
}

str_replace干扰

6 个答案: