我有一个UITextView,我需要检测用户是否输入表情符号字符。
我认为只检查最新字符的unicode值就足够了,但是对于新的表情符号2s,一些字符分散在整个unicode索引中(即Apple新设计的版权和注册徽标)。
也许与使用NSLocale或LocalizedString值检查字符的语言有关?
有谁知道一个好的解决方案?
谢谢!
答案 0 :(得分:17)
多年来,这些表情符号检测解决方案不断突破,因为Apple添加了新的表情符号(如通过预先诅咒带有附加角色的角色制作的肤色表情符号)等等。
我终于崩溃了,只是编写了以下方法,该方法适用于所有当前的表情符号,并且应该适用于所有未来的表情符号。
该解决方案创建了一个带有角色和黑色背景的UILabel。然后,CG拍摄标签的快照,并扫描快照中的所有像素,以查找任何非纯黑像素。我添加黑色背景的原因是为了避免由Subpixel Rendering
引起的假色问题解决方案在我的设备上运行非常快,我可以每秒检查数百个字符,但应该注意这是一个CoreGraphics解决方案,不应像使用常规文本方法那样大量使用。图形处理数据量很大,因此一次检查数千个字符可能会导致明显的延迟。
-(BOOL)isEmoji:(NSString *)character {
UILabel *characterRender = [[UILabel alloc] initWithFrame:CGRectMake(0, 0, 1, 1)];
characterRender.text = character;
characterRender.backgroundColor = [UIColor blackColor];//needed to remove subpixel rendering colors
[characterRender sizeToFit];
CGRect rect = [characterRender bounds];
UIGraphicsBeginImageContextWithOptions(rect.size,YES,0.0f);
CGContextRef contextSnap = UIGraphicsGetCurrentContext();
[characterRender.layer renderInContext:contextSnap];
UIImage *capturedImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
CGImageRef imageRef = [capturedImage CGImage];
NSUInteger width = CGImageGetWidth(imageRef);
NSUInteger height = CGImageGetHeight(imageRef);
CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB();
unsigned char *rawData = (unsigned char*) calloc(height * width * 4, sizeof(unsigned char));
NSUInteger bytesPerPixel = 4;
NSUInteger bytesPerRow = bytesPerPixel * width;
NSUInteger bitsPerComponent = 8;
CGContextRef context = CGBitmapContextCreate(rawData, width, height,
bitsPerComponent, bytesPerRow, colorSpace,
kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big);
CGColorSpaceRelease(colorSpace);
CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef);
CGContextRelease(context);
BOOL colorPixelFound = NO;
int x = 0;
int y = 0;
while (y < height && !colorPixelFound) {
while (x < width && !colorPixelFound) {
NSUInteger byteIndex = (bytesPerRow * y) + x * bytesPerPixel;
CGFloat red = (CGFloat)rawData[byteIndex];
CGFloat green = (CGFloat)rawData[byteIndex+1];
CGFloat blue = (CGFloat)rawData[byteIndex+2];
CGFloat h, s, b, a;
UIColor *c = [UIColor colorWithRed:red green:green blue:blue alpha:1.0f];
[c getHue:&h saturation:&s brightness:&b alpha:&a];
b /= 255.0f;
if (b > 0) {
colorPixelFound = YES;
}
x++;
}
x=0;
y++;
}
return colorPixelFound;
}
答案 1 :(得分:3)
另一种解决方案:https://github.com/woxtu/NSString-RemoveEmoji
然后,在导入此扩展程序后,您可以像这样使用它:
- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text
{
// Detect if an Emoji is in the string "text"
if(text.isIncludingEmoji) {
// Show an UIAlertView, or whatever you want here
return NO;
}
return YES;
}
希望有所帮助;)
答案 2 :(得分:3)
首先让我们解决您的“55357方法” - 和为什么它适用于许多表情符号字符。
在Cocoa中,NSString
是unichar
的集合,unichar
只是unsigned short
的一个类型,与UInt16
相同。由于UInt16
的最大值为0xffff
,因此可以将一些表情符号排除在一个unichar
之外,因为用于表情符号的六个主要Unicode块中只有两个属于这个范围:
这些块包含113个表情符号,另外66个可以表示为单个unichar
的表情符号可以在各个其他块周围找到。但是,这179个字符仅代表1126 emoji base characters的一小部分,其余部分必须由多个unichar
表示。
让我们分析您的代码:
unichar unicodevalue = [text characterAtIndex:0];
正在发生的事情是你只是接受字符串的第一个unichar
,虽然这适用于前面提到的179个字符,但是当遇到UTF-32字符时,它会分开,因为{{1将所有内容转换为UTF-16编码。转化工作substituting the UTF-32 value with surrogate pairs,这意味着NSString
现在包含两个NSString
。
现在我们已经了解为什么数字55357或unichar
出现在许多表情符号中:当你只查看UTF-32的第一个UTF-16值时你获得高代理人的角色,每个代理人都有1024个低代理人。高代理0xd83d
的范围是U + 1F400-U + 1F7FF,它从最大的表情符号块Miscellaneous Symbols and Pictographs(U + 1F300-U + 1F5FF)的中间开始,并继续全部直至Geometric Shapes Extended(U + 1F780-U + 1F7FF) - 在此范围内共包含563个表情符号和333个非表情符号字符。
因此,令人印象深刻的50%的表情符号基础字符具有高代理0xd83d
,但这些演绎方法仍然留下384个表情符号字符未处理,并且至少给出了误报率。
我最近回答了somewhat related question with a Swift implementation,如果您愿意,可以查看this framework中我是如何检测表情符号的,这是为了用自定义图像替换标准表情符号而创建的。
无论如何,你可以做的是从字符中提取UTF-32代码点,我们将根据the specification执行:
0xd83d
在- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {
// Get the UTF-16 representation of the text.
unsigned long length = text.length;
unichar buffer[length];
[text getCharacters:buffer];
// Initialize array to hold our UTF-32 values.
NSMutableArray *array = [[NSMutableArray alloc] init];
// Temporary stores for the UTF-32 and UTF-16 values.
UTF32Char utf32 = 0;
UTF16Char h16 = 0, l16 = 0;
for (int i = 0; i < length; i++) {
unichar surrogate = buffer[i];
// High surrogate.
if (0xd800 <= surrogate && surrogate <= 0xd83f) {
h16 = surrogate;
continue;
}
// Low surrogate.
else if (0xdc00 <= surrogate && surrogate <= 0xdfff) {
l16 = surrogate;
// Convert surrogate pair to UTF-32 encoding.
utf32 = ((h16 - 0xd800) << 10) + (l16 - 0xdc00) + 0x10000;
}
// Normal UTF-16.
else {
utf32 = surrogate;
}
// Add UTF-32 value to array.
[array addObject:[NSNumber numberWithUnsignedInteger:utf32]];
}
NSLog(@"%@ contains values:", text);
for (int i = 0; i < array.count; i++) {
UTF32Char character = (UTF32Char)[[array objectAtIndex:i] unsignedIntegerValue];
NSLog(@"\t- U+%x", character);
}
return YES;
}
中键入“”将此内容写入控制台:
UITextView
使用该逻辑,只需将 contains values:
- U+1f60e
的值与表情符号代码点的数据源进行比较,您就会确切地知道该字符是否为表情符号。
P.S。
有一些“隐形”字符,即Variation Selectors和zero-width joiners,也应该处理,所以我建议研究那些以了解它们的行为。< / p>
答案 3 :(得分:2)
如果您不希望键盘显示表情符号,则可以使用
YOURTEXTFIELD/YOURTEXTVIEW.keyboardType = .ASCIICapable
这将显示没有表情符号的键盘
答案 4 :(得分:2)
这是快速中的表情符号检测方法。工作正常。希望对别人有帮助。
func isEmoji(_ character: String?) -> Bool {
if character == "" || character == "\n" {
return false
}
let characterRender = UILabel(frame: CGRect(x: 0, y: 0, width: 1, height: 1))
characterRender.text = character
characterRender.backgroundColor = UIColor.black
characterRender.sizeToFit()
let rect: CGRect = characterRender.bounds
UIGraphicsBeginImageContextWithOptions(rect.size, true, 0.0)
if let contextSnap:CGContext = UIGraphicsGetCurrentContext() {
characterRender.layer.render(in: contextSnap)
}
let capturedImage: UIImage? = (UIGraphicsGetImageFromCurrentImageContext())
UIGraphicsEndImageContext()
var colorPixelFound:Bool = false
let imageRef = capturedImage?.cgImage
let width:Int = imageRef!.width
let height:Int = imageRef!.height
let colorSpace = CGColorSpaceCreateDeviceRGB()
let rawData = calloc(width * height * 4, MemoryLayout<CUnsignedChar>.stride).assumingMemoryBound(to: CUnsignedChar.self)
let bytesPerPixel:Int = 4
let bytesPerRow:Int = bytesPerPixel * width
let bitsPerComponent:Int = 8
let context = CGContext(data: rawData, width: Int(width), height: Int(height), bitsPerComponent: Int(bitsPerComponent), bytesPerRow: Int(bytesPerRow), space: colorSpace, bitmapInfo: CGImageAlphaInfo.premultipliedLast.rawValue | CGBitmapInfo.byteOrder32Big.rawValue)
context?.draw(imageRef!, in: CGRect(x: 0, y: 0, width: width, height: height))
var x:Int = 0
var y:Int = 0
while (y < height && !colorPixelFound) {
while (x < width && !colorPixelFound) {
let byteIndex: UInt = UInt((bytesPerRow * y) + x * bytesPerPixel)
let red = CGFloat(rawData[Int(byteIndex)])
let green = CGFloat(rawData[Int(byteIndex+1)])
let blue = CGFloat(rawData[Int(byteIndex + 2)])
var h: CGFloat = 0.0
var s: CGFloat = 0.0
var b: CGFloat = 0.0
var a: CGFloat = 0.0
var c = UIColor(red:red, green:green, blue:blue, alpha:1.0)
c.getHue(&h, saturation: &s, brightness: &b, alpha: &a)
b = b/255.0
if Double(b) > 0.0 {
colorPixelFound = true
}
x+=1
}
x=0
y+=1
}
return colorPixelFound
}
答案 5 :(得分:0)
以下是代码的更干净,更高效的实现,该代码检查以查看绘制的字符是否具有任何颜色。
这些已被编写为类别/扩展方法,以使其更易于使用。
Objective-C:
NSString + Emoji.h:
#import <Foundation/Foundation.h>
@interface NSString (Emoji)
- (BOOL)hasColor;
@end
NSString + Emoji.m:
#import "NSString+Emoji.h"
#import <UIKit/UIKit.h>
@implementation NSString (Emoji)
- (BOOL)hasColor {
UILabel *characterRender = [[UILabel alloc] initWithFrame:CGRectZero];
characterRender.text = self;
characterRender.textColor = UIColor.blackColor;
characterRender.backgroundColor = UIColor.blackColor;//needed to remove subpixel rendering colors
[characterRender sizeToFit];
CGRect rect = characterRender.bounds;
UIGraphicsBeginImageContextWithOptions(rect.size, YES, 1);
CGContextRef contextSnap = UIGraphicsGetCurrentContext();
[characterRender.layer renderInContext:contextSnap];
UIImage *capturedImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
CGImageRef imageRef = capturedImage.CGImage;
size_t width = CGImageGetWidth(imageRef);
size_t height = CGImageGetHeight(imageRef);
CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB();
size_t bytesPerPixel = 4;
size_t bitsPerComponent = 8;
size_t bytesPerRow = bytesPerPixel * width;
size_t size = height * width * bytesPerPixel;
unsigned char *rawData = (unsigned char *)calloc(size, sizeof(unsigned char));
CGContextRef context = CGBitmapContextCreate(rawData, width, height,
bitsPerComponent, bytesPerRow, colorSpace,
kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big);
CGColorSpaceRelease(colorSpace);
CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef);
CGContextRelease(context);
BOOL result = NO;
for (size_t offset = 0; offset < size; offset += bytesPerPixel) {
unsigned char r = rawData[offset];
unsigned char g = rawData[offset+1];
unsigned char b = rawData[offset+2];
if (r || g || b) {
result = YES;
break;
}
}
free(rawData);
return result;
}
@end
用法示例:
if ([@"?" hasColor]) {
// Yes, it does
}
if ([@"@" hasColor]) {
} else {
// No, it does not
}
快捷键:
String + Emoji.swift:
import UIKit
extension String {
func hasColor() -> Bool {
let characterRender = UILabel(frame: .zero)
characterRender.text = self
characterRender.textColor = .black
characterRender.backgroundColor = .black
characterRender.sizeToFit()
let rect = characterRender.bounds
UIGraphicsBeginImageContextWithOptions(rect.size, true, 1)
let contextSnap = UIGraphicsGetCurrentContext()!
characterRender.layer.render(in: contextSnap)
let capturedImageTmp = UIGraphicsGetImageFromCurrentImageContext()
UIGraphicsEndImageContext()
guard let capturedImage = capturedImageTmp else { return false }
let imageRef = capturedImage.cgImage!
let width = imageRef.width
let height = imageRef.height
let colorSpace = CGColorSpaceCreateDeviceRGB()
let bytesPerPixel = 4
let bytesPerRow = bytesPerPixel * width
let bitsPerComponent = 8
let size = width * height * bytesPerPixel
let rawData = calloc(size, MemoryLayout<CUnsignedChar>.stride).assumingMemoryBound(to: CUnsignedChar.self)
guard let context = CGContext(data: rawData, width: width, height: height, bitsPerComponent: bitsPerComponent, bytesPerRow: bytesPerRow, space: colorSpace, bitmapInfo: CGImageAlphaInfo.premultipliedLast.rawValue | CGBitmapInfo.byteOrder32Big.rawValue) else { return false }
context.draw(imageRef, in: CGRect(x: 0, y: 0, width: width, height: height))
var result = false
for offset in stride(from: 0, to: size, by: 4) {
let r = rawData[offset]
let g = rawData[offset + 1]
let b = rawData[offset + 2]
if (r > 0 || g > 0 || b > 0) {
result = true
break
}
}
free(rawData)
return result
}
}
用法示例:
if "?".hasColor() {
// Yes, it does
}
if "@".hasColor() {
} else {
// No, it does not
}
答案 6 :(得分:0)
Swift的String类型具有.isEmoji属性
最好查看isEmojiPresentation警告的文档
https://developer.apple.com/documentation/swift/unicode/scalar/properties/3081577-isemoji
答案 7 :(得分:-3)
你可以用它来检测它是否只有ascii字符:
[myString canBeConvertedToEncoding:NSASCIIStringEncoding];
如果失败(或有表情符号),它会说不。然后你可以做一个if else语句,不允许他们点击回车或其他东西。
答案 8 :(得分:-4)
表情符号字符长度为2,因此检查字符串长度是否为2,方法是shouldChangeTextInRange:在键盘命中每个键后调用
- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text
{
// Detect if an Emoji is in the string "text"
if([text length]==2) {
// Show an UIAlertView, or whatever you want here
return YES;
}
else
{
return NO;
}
}