Question

我在spring 3中使用java servlet。有没有办法检查是否有特定URL的处理程序？

我正在尝试实施一项测试，以确保处理我的Jsp文件中使用的所有网址。如果我想进行网址重构，我想确保没有任何“破解链接”。在我的jsps ...

由于

Answer 1

如果你正在使用JUnit和Spring 3，这里是一个FooController测试的例子：

@Controller
@RequestMapping(value = "/foo")
public class FooAdminController {

    @RequestMapping(value = "/bar")
    public ModelAndView bar(ModelAndView mav) {

        mav.setViewName("bar");
        return mav;
    }
}

FooController的测试用例：

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration({"file:src/path/to/servlet-context.xml" })
public class FooControllerTest {

    @Autowired
    private RequestMappingHandlerMapping handlerMapping;

    @Autowired
    private RequestMappingHandlerAdapter handleAdapter;

    @Test
    public void fooControllerTest() throws Exception{

        // Create a Mock implementation of the HttpServletRequest interface
        MockHttpServletRequest request = new MockHttpServletRequest();

        // Create Mock implementation of the HttpServletResponse interface
        MockHttpServletResponse response = new MockHttpServletResponse();

        // Define the request URI needed to test a method on the FooController
        request.setRequestURI("/foo/bar");

        // Define the HTTP Method
        request.setMethod("GET");

        // Get the handler and handle the request
        Object handler = handlerMapping.getHandler(request).getHandler();
        ModelAndView handleResp = handleAdapter.handle(request, response, handler);

        // Test some ModelAndView properties
        ModelAndViewAssert.assertViewName(handleResp ,"bar");
        assertEquals(200, response.getStatus());
    }
}

Spring 3检查是否有url的处理程序

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