我正在为实体对象上的延迟加载集合执行此操作:
@Transactional(readOnly = true)
public T getWithAssociation(final long id, String association) {
Session session = sessionFactory.getCurrentSession();
final Criteria crit = session.createCriteria(genericType);
crit.setFetchMode(association, FetchMode.JOIN);
crit.add(Property.forName("id").eq(id));
return (T) crit.uniqueResult();
}
我想返回一个带有多个延迟加载的集合已加载的实体对象,我可以这样做(传入列表并为单个条件设置多个关联吗?):
@Transactional(readOnly = true)
public T getWithAssociations(final long id, List<String> associations) {
Session session = sessionFactory.getCurrentSession();
final Criteria crit = session.createCriteria(genericType);
for(String association:associations) {
crit.setFetchMode(association, FetchMode.JOIN);
}
crit.add(Property.forName("id").eq(id));
return (T) crit.uniqueResult();
}
答案 0 :(得分:3)
是
docs包含以下内容:
List cats = sess.createCriteria(Cat.class)
.add( Restrictions.like("name", "Fritz%") )
.setFetchMode("mate", FetchMode.EAGER)
.setFetchMode("kittens", FetchMode.EAGER)
.list();
此查询将通过外部联接获取配偶和小猫。有关更多信息,请参见第20.1节“获取策略”。