Question

我正在玩一点拖累和放放弃ui，我对 DROP 感到有点难过。
您可以 see the Fiddle here 。

立即目标：
我只需要了解如何将.draggable范围转换为.droppable div中的任何一个假设我在append()的正确路径上，如何访问克隆的内容？

终极目标：
最后，我需要添加一种方法来删除drop-zone div中的项目，并将.textfield input / div限制为只接受一个drop（.textarea input / div可以接受无限制“有效载荷”的数量。）

CODE：

/* html */
<table>
    <thead>    
        <tr role="row">
            <th class="sorting_asc" role="columnheader" tabindex="0" aria-controls="DataTables_Table_0" rowspan="1" colspan="1" style="width: 494px;" aria-sort="ascending" aria-label="Company: activate to sort column descending">Company</th>
            <th class="sorting_disabled" role="columnheader" rowspan="1" colspan="1" style="width: 66px;" aria-label="Contact">Contact</th>
            <th class="sorting_disabled" role="columnheader" rowspan="1" colspan="1" style="width: 79px;" aria-label="&amp;nbsp;">&nbsp;</th>
        </tr>
    </thead>
    <tbody role="alert" aria-live="polite" aria-relevant="all">
        <tr class="odd">
            <td class="sorting_1 has_draggable_children">
                <span draggable="true" class="ui-draggable" data-companyid="0101" data-companyname="**BD">**BD</span>
            </td>
            <td><a href="#4621">Contacts</a></td>
            <td><a href="#4621">Edit</a>
                <a href="#4621">Delete</a>
            </td>
        </tr>
        <tr class="even">
            <td class="sorting_1 has_draggable_children">
                <span draggable="true" data-companyid="0202" data-companyname="0024" class="ui-draggable">0024</span>
            </td>
            <td><a href="#4438">Contacts</a></td>
            <td><a href="#4438">Edit</a>
                <a href="#4438">Delete</a>
            </td>
        </tr>
        <tr class="odd">
            <td class="sorting_1 has_draggable_children">
                <span draggable="true" class="ui-draggable" data-companyid="0303" data-companyname="Acme, Inc.">Acme Anvil Corp</span>
            </td>
            <td><a href="#4621">Contacts</a></td>
            <td><a href="#4621">Edit</a>
                <a href="#4621">Delete</a>
            </td>
        </tr>
   </tbody>
</table>

<section class="offset7" id="dragged-drop-zone" >
    <div class="look-like-input textfield droppable" contenteditable></div>
    <br />
    <div class="look-like-input textarea droppable" contenteditable></div>
</section>

/* js */
// DRAG
$('span[draggable]').draggable({
    revert: true,
    helper: "clone"
});

// DROP
$('.droppable').droppable({
    tolerance: 'pointer',
    drop: function(event, ui) {
        //console.log(this);
        $(this).append($(ui.helper));
    }
});

欢迎提供任何帮助和建议

Answer 1

好吧......到了底部。

clone 似乎并没有像人们期望的那样运作。您最终必须使用自定义函数将自己的克隆打包到对象中，然后在drop中将其从对象中拉回来。

您可以在jsFiddle上 see the working example here 以下是最终工作的内容：

// Drag
$('span[draggable]').draggable({
    revert: true,
    helper: function() {
        var container = $('<div/>');
        var dragged = $(this);
        container.append(dragged.clone());
        return container;
    }
});

// Drop
$('.droppable').droppable({
    tolerance: 'pointer',
    drop: function(event, ui) {
        $(this).append($(ui.helper.children()));
    }
});

jQuery UI拖放：克隆不丢弃

1 个答案: