Question

对不起，但我的数学和物理太弱，所以我尝试了很多次但每次我都失败了我需要你的帮助来完成我的应用程序plz将这个圆圈转换为心脏

import android.graphics.Bitmap;
public class Circle {
float origRadius,deltaRadius,radius,origX,deltaX,x,origY,deltaY,y;
int color,alpha,steps,currentStep;
Bitmap bitmap;

public Circle(float xCenter, float yCenter, float radius,
        int color, int steps) {
    this.x = xCenter;
    this.origX = xCenter;
    this.deltaX = (float) (40.0 * Math.random() - 20.0);

    this.y = yCenter;
    this.origY = yCenter;
    this.deltaY = (float) (40.0 * Math.random() - 20.0);

    this.origRadius = radius;
    this.radius = radius;
    this.deltaRadius = 0.5f * radius;

    this.color = color;
    this.alpha = 0;

    this.steps = steps;
}

void tick() {
    this.currentStep++;

    float fraction = (float) this.currentStep / (float) this.steps;

    this.radius = this.origRadius + fraction * this.deltaRadius;
    this.x = this.origX + fraction * this.deltaX;
    this.y = this.origY + fraction * this.deltaY;

    if (fraction <= 0.25f) {
        this.alpha = (int) (128 * 4.0f * fraction);
    } else {
        this.alpha = (int) (-128 * (fraction - 1) / 0.75f);
    }
}

boolean isDone() {
    return this.currentStep > this.steps;
}
}

提前致谢

Answer 1

MathWorld具有很棒的心形功能; http://mathworld.wolfram.com/HeartCurve.html

基本上你必须在你的代码中做这样的事情;

float fraction = (float) this.currentStep / (float) this.steps;

- ＆GT;

float t = this.currentStep * 2.0 * Math.PI / (float) this.steps;

this.x = 16.0 * Math.pow(Math.sin(t), 3.0));
this.y = 13.0 * Math.cos(t) - 5.0 * Math.cos(2.0 * t) -
          2.0 * Math.cos(3.0 * t) - Math.cos(4.0 * t);

希望这会有所帮助，我会盲目地写这篇文章，如果出现一些错误，请耐心等待。对于radius，您可能想要做这样的事情;

this.x *= radius / 16.0;
this.y *= radius / 16.0;

将圆圈转换为心脏2d android

1 个答案: