Question

目前，我的代码产生了这样的结果：

 SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS  MONTH, COUNT(*) AS TOTAL
 FROM news
 GROUP BY MONTH 

 UNION ALL 

 SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH , COUNT(*) AS TOTAL
 FROM equipment
 GROUP BY MONTH 

 RESULTS:
 YEAR MONTH TOTAL
 2013 FEB    1 (news table)
 2013 JAN   12 (news table)
 2013 FEB    1 (equipment table)
 2013 JAN   11 (equipment table)

如何编辑SQL查询，以便我只能显示：

 RESULTS:
 YEAR MONTH TOTAL
 2013 FEB    2 (both news and equipment table)
 2013 JAN   23 (both news and equipment table)

提前感谢您的帮助！

Answer 1

尝试：

SELECT YEAR, MONTH, SUM(TOTAL) AS TOTAL
FROM (SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS  MONTH, COUNT(*) AS TOTAL
 FROM news
 GROUP BY MONTH 

 UNION ALL 

 SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH , COUNT(*) AS TOTAL
 FROM equipment
 GROUP BY MONTH) x
GROUP BY YEAR, MONTH

Answer 2

试

Select year, month, sum(total) from
(
SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS  MONTH, COUNT(*) AS TOTAL
 FROM news
 GROUP BY MONTH 

 UNION ALL 

 SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH , COUNT(*) AS TOTAL
 FROM equipment
 GROUP BY MONTH 
)
group by year, month

Answer 3

试试这个：

SELECT YEAR, MONTH, SUM(total) total 
FROM (SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH, COUNT(*) AS TOTAL 
      FROM news 
      GROUP BY MONTH
      UNION ALL
      SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH , COUNT(*) AS TOTAL 
      FROM equipment 
      GROUP BY MONTH
     ) AS A 
GROUP BY YEAR, MONTH

Answer 4

select x.year, x.month, sum(x.total) from x(
 SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS  MONTH, COUNT(*) AS TOTAL
 FROM news
 GROUP BY MONTH 

 UNION ALL 

 SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH , COUNT(*) AS TOTAL
 FROM equipment
 GROUP BY MONTH ) x
group by x.month, x.year

如何按月对结果进行分组？

4 个答案: