我在MongoDB中有一个ISSUES数据库,其中一些问题有注释,这是一个数组;每个评论都有一个作家。我如何计算每位作者写的评论数量?
我试过
db.test.issues.group(
{
key = "comments.username":true;
initial: {sum:0},
reduce: function(doc, prev) {prev.sum +=1},
}
);
但没有运气:(
样本:
{
"_id" : ObjectId("50f48c179b04562c3ce2ce73"),
"project" : "Ruby Driver",
"key" : "RUBY-505",
"title" : "GETMORE is sent to wrong server if an intervening query unpins the connection",
"description" : "I've opened a pull request with a failing test case demonstrating the bug here: https://github.com/mongodb/mongo-ruby-driver/pull/134\nExcerpting that commit message, the issue is: If we do a secondary read that is large enough to require sending a GETMORE, and then do another query before the GETMORE, the secondary connection gets unpinned, and the GETMORE gets sent to the wrong server, resulting in CURSOR_NOT_FOUND, even though the cursor still exis ts on the server that was initially queried.",
"status" : "Open",
"components" : [
"Replica Set"
],
"affected_versions" : [
"1.7.0"
],
"type" : "Bug",
"reporter" : "Nelson Elhage",
"priority" : "major",
"assignee" : "Tyler Brock",
"resolution" : "Unresolved",
"reported_on" : ISODate("2012-11-17T20:30:00Z"),
"votes" : 3,
"comments" : [
{
"username" : "Nelson Elhage",
"date" : ISODate("2012-11-17T20:30:00Z"),
"body" : "Thinking some more"
},
{
"username" : "Brandon Black",
"date" : ISODate("2012-11-18T20:30:00Z"),
"body" : "Adding some findings of mine to this ticket."
},
{
"username" : "Nelson Elhage",
"date" : ISODate("2012-11-18T20:30:00Z"),
"body" : "I think I tracked down the 1.9 dependency."
},
{
"username" : "Nelson Elhage",
"date" : ISODate("2012-11-18T20:30:00Z"),
"body" : "Forgot to include a link"
}
]
}
答案 0 :(得分:3)
您忘记了key
值上的花括号,您需要使用,
而不是;
来终止该行。
db.issues.group({
key: {"comments.username":true},
initial: {sum:0},
reduce: function(doc, prev) {prev.sum +=1},
});
<强>更新强>
在认识到comments
是一个数组之后......您需要使用aggregate
,以便您可以“展开”comments
然后对其进行分组:
db.issues.aggregate(
{$unwind: '$comments'},
{$group: {_id: '$comments.username', sum: {$sum: 1}}}
);
对于问题中的示例文档,此输出:
{
"result": [
{
"_id": "Brandon Black",
"sum": 1
},
{
"_id": "Nelson Elhage",
"sum": 3
}
],
"ok": 1
}
答案 1 :(得分:1)
这里只是一个讽刺的回答来赞美@JohnnyHKs回答:这听起来像是MongoDB的新手,因此可能会在新版本的MongoDB上工作,如果是这样的话(如果不是我会升级的话)那么旧的{{ 1}}计数有点不好。例如,它不会与分片一起使用。
而在MongoDB 2.2中你可以这样做:
group
或类似的东西。您可以在此处详细了解:http://docs.mongodb.org/manual/applications/aggregation/