对于定义如下的实体:
@Entity
public class Acl implements Serializable {
@Id
@GeneratedValue
@Column(name = "acl_id")
private Long id;
@ElementCollection(fetch=FetchType.EAGER)
@JoinTable(name = "acl_permits")
private Map<String, Integer> permits = new HashMap<String, Integer>();
查询:
query = em.createQuery("select a FROM Acl a " +
"JOIN a.permits p WITH KEY(p) = '" + user + "' and VALUE(p) = " + permit + "");
转换为:
select acl0_.acl_id as acl1_1_ from Acl acl0_
inner join acl_permits permits1_ on acl0_.acl_id=permits1_.Acl_acl_id
and (permits1_.permits_KEY='user1'
and (select permits1_.permits from acl_permits permits1_ where acl0_.acl_id=permits1_.Acl_acl_id)=1)
为了将它转换成什么是查询?:
select acl0_.acl_id as acl1_1_ from Acl acl0_
inner join acl_permits permits1_ on acl0_.acl_id=permits1_.Acl_acl_id
and (permits1_.permits_KEY='user1' and acl0_.acl_id=permits1_.Acl_acl_id=1)
答案 0 :(得分:0)
您可以在JPA中使用本机SQL。所以你可以这样做。
query = em.createNativeQuery("select acl0_.acl_id as acl1_1_ from Acl acl0_
inner join acl_permits permits1_ on acl0_.acl_id=permits1_.Acl_acl_id
and (permits1_.permits_KEY=?user and acl0_.acl_id=permits1_.Acl_acl_id=?permit_id)");