Question

我希望在其他地方没有问过这个问题因为我看了但是现在这样。我写了这个函数来为我创建表。它有效，但我遇到的问题是它每次调用此函数时都会运行查询。有没有办法调用此函数并将查询传递给函数？

function createawardtables($awardname, $awardshortname, $maxawards, $id){    
    $query="SELECT * FROM awards WHERE id = $id";
    $result = mysql_query($query) or die("There was a problem with the SQL query: " . mysql_error());
    while($row = mysql_fetch_array($result)){
        $order = array("","1st","2nd","3rd","4th","5th","6th","7th","8th",'9th',"10th");
        echo "<table><th colspan=4><font color=maroon  size='4pt'><u><b>Orders of the $awardfullname</b></u></font></th>";   
        for($i=1; $i<$maxawards+1; $i++) {
            ${$awardshortname.$i} = dateconvert(($row["$awardshortname$i"]), 2);
            ${$awardshortname.$i.'by'} = $row["$awardshortname{$i}by"];
            ${$awardshortname.$i.'memo'} = $row["$awardshortname{$i}memo"];
            echo "<tr>
                <td>$order[$i] Order given on </td>
                <td><input type=text name='$awardshortname$i' title='mm/dd/yyyy' value= '${$awardshortname.$i}' size=8/></td>
                <td>by <input type=text name='$awardshortname{$i}by' title='Name of who gave the award.' value='${$awardshortname.$i.'by'}'size=15/></td>
                <td>for <input type=text name='$awardshortname{$i}memo' title='What the award was give for.' value='${$awardshortname.$i.'memo'}'size=15/></td>
                </tr>";

            if($i==10 or $awardshortname=="initiate"){
            echo "</table><br />";

            };
        };
    };
    mysql_free_result($result); 
};

Answer 1

当然，只需在函数中添加一个新参数（如$awardname），并在调用'mysql_query（）`时使用它。

另外请注意，强烈建议不要使用mysql_*函数：

自PHP 5.5.0起，此扩展程序已弃用，并将在中删除未来。相反，应该使用MySQLi或PDO_MySQL扩展。

http://www.php.net/mysql_query

Answer 2

你去吧

function createawardtables($result, $awardname, $awardshortname, $maxawards, $id)
{    
    while($row = mysql_fetch_array($result)){
        $order = array("","1st","2nd","3rd","4th","5th","6th","7th","8th",'9th',"10th");
        echo "<table><th colspan=4><font color=maroon  size='4pt'><u><b>Orders of the $awardfullname</b></u></font></th>";   
        for($i=1; $i<$maxawards+1; $i++) {
            ${$awardshortname.$i} = dateconvert(($row["$awardshortname$i"]), 2);
            ${$awardshortname.$i.'by'} = $row["$awardshortname{$i}by"];
            ${$awardshortname.$i.'memo'} = $row["$awardshortname{$i}memo"];
            echo "<tr>
                <td>$order[$i] Order given on </td>
                <td><input type=text name='$awardshortname$i' title='mm/dd/yyyy' value= '${$awardshortname.$i}' size=8/></td>
                <td>by <input type=text name='$awardshortname{$i}by' title='Name of who gave the award.' value='${$awardshortname.$i.'by'}'size=15/></td>
                <td>for <input type=text name='$awardshortname{$i}memo' title='What the award was give for.' value='${$awardshortname.$i.'memo'}'size=15/></td>
                </tr>";

            if($i==10 or $awardshortname=="initiate"){
            echo "</table><br />";

            };
        };
    };
    mysql_free_result($result); 
};

和函数调用

$query="SELECT * FROM awards WHERE id = $id";
$result = mysql_query($query) or die("There was a problem with the SQL query: " . mysql_error());
createawardtables($result, $awardname, $awardshortname, $maxawards, $id);

有没有办法将查询传递给php函数

2 个答案: