使用hibernate获取基于类似'123%'的sql结果

时间:2013-01-14 10:41:05

标签: java hibernate jpa

我正在使用Hibernate 4,我想在我的DAO类中使用以下代码 从我的表中获得结果

CriteriaBuilder cb = entityManager.getCriteriaBuilder();
        CriteriaQuery<Employee> c = cb.createQuery(Employee.class);
        Root<Employee> emp = c.from(Employee.class);
        c.select(emp);
List<Predicate> criteria = new ArrayList<Predicate>();
ParameterExpression<String> pexp = cb.parameter(String.class,
                "employeeNumber");
Predicate predicate = cb.like(emp.get(Employee_.employeeNumber),
                pexp);

        criteria.add(predicate);

if (criteria.size() == 1) {
            c.where(criteria.get(0));           
        } else if (criteria.size() > 1) {
            c.where(cb.and(criteria.toArray(new Predicate[0])));

        }

TypedQuery<Employee> q = entityManager.createQuery(c);
if (employeeNumber != null) {
            q.setParameter("employeeNumber", employeeNumber);
data.setResult(q.getResultList());

当页面运行时,从日志中我可以看到sql为

select employeede0_.EMPLOYEE_NUMBER as EMPLOYEE1_0_ from EMPLOYEES employeede0_ 
where employeede0_.EMPLOYEE_NUMBER like ?

因此,我无法看到任何结果。理想情况下,我希望有一个像

这样的查询
select employeede0_.EMPLOYEE_NUMBER as EMPLOYEE1_0_ from EMPLOYEES employeede0_ 
    where employeede0_.EMPLOYEE_NUMBER like '123%'

我怎样才能做到这一点?

2 个答案:

答案 0 :(得分:2)

您希望最终执行

Predicate predicate = cb.like("employeeNumber", "123%");

所以包括百分比。

答案 1 :(得分:1)

这应该适合你:

criteria.add ( Restrictions.like ("employeeNumber", "123%" ) );