Question

我正在尝试将字符串转换为url但未获得成功。任何更好的方法，或改进下面的代码。感谢

NSString *strURL = @"http://domain.com/This Is My, Code for This. app";
NSString *escapedUrlString = [strURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog(escapedUrlString);

显示此日志

http://domain.com/This2s2y，芙赋
0.000000or2his.20x1.55e800047f4p-1029pp

这是我的实际代码发送和保存数据到mysql

NSString *data = @"This Is My, Code for This. app";
NSString *strURL = [NSString stringWithFormat:@"http://domain.com/connection.php?data=%@", data];   

NSData *dataURL = [NSData dataWithContentsOfURL:[NSURL URLWithString:strURL]];


NSString *strResult = [[NSString alloc] initWithData:dataURL encoding:NSUTF8StringEncoding];  

NSURL *urll = [NSURL URLWithString:strResult];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:urll];

[request setHTTPMethod:@"GET"];


NSURLResponse *response;
NSError *err;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&err];
NSLog(@"responseData: %@", responseData);

没有成功，但是当我使用

时

data = @"ThisIsMyCode";

然后一切正常...... 帮助

Answer 1

NSString *data = @"This Is My, Code for This. app";
NSString *escapedDataString = [data stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

NSString *strURL = [NSString stringWithFormat:@"http://domain.com/connection.php?data=%@", escapedDataString];
    NSLog(@"Encoded:%@",strURL);

这很好用，这是日志：

Encoded:http://domain.com/connection.php?data=This%20Is%20My,%20Code%20for%20This.%20app

将字符串转换为url以将数据发送到mysql objective c iOS

1 个答案: