MySQLSyntaxErrorException

时间:2013-01-14 02:42:17

标签: java mysql jdbc phpmyadmin

我刚开始学习MySQL和JDBC。

我使用phpmyadmin创建了一个名为testdb的表。表只有2列,分别为first和last。当我尝试从我的java类连接数据库时,我得到了MySQLSyntaxError。但是我无法理解。

这是我的班级:

import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;

public class Main {

    public static void main(String[] args) throws ClassNotFoundException, SQLException {
        String url = "jdbc:mysql://localhost:3306/testdb";

        //Accessing driver from the JAR file.
        Class.forName("com.mysql.jdbc.Driver");

        //Creating a variable for the connection "con"
        Connection con = DriverManager.getConnection(url,"root","password");

        //Here is the query
        PreparedStatement statement = con.prepareStatement("select * from name");

        //Execute query
        ResultSet result = statement.executeQuery();

        while(result.next()) {
            System.out.println(result.getString(1) + " " + result.getString(2));
        }


    }

}

以下是例外:

Exception in thread "main" com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Table 'testdb.name' doesn't exist
    at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:57)
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45)
    at java.lang.reflect.Constructor.newInstance(Constructor.java:525)
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:411)
    at com.mysql.jdbc.Util.getInstance(Util.java:386)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1053)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4096)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4028)
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2490)
    at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2651)
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2734)
    at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2155)
    at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:2322)
    at Main.main(Main.java:22)

感谢您的帮助

2 个答案:

答案 0 :(得分:2)

MySQLSyntaxErrorException: Table 'testdb.name' doesn't exist

错误几乎是描述性的。没有名称和#34;名称"在testdb架构中。

  

我使用phpmyadmin创建了一个名为 testdb 的表。

如果您已创建表testdb,那么它应为select * from testdb。不是吗?

答案 1 :(得分:2)

您已创建名为 testdb 的表格,因此您的查询应为

select * from testdb 

不是select * from name

你应该检查你的堆栈痕迹。