我有一个特定数量的进程(C#.exe)应该启动。我如何根据他们的优先级启动它们。
我知道Process.PriorityClass的东西,但它并没有用,因为它只在启动进程后分配优先级。
我这里有这个代码(不比较优先级)但它不起作用,因为没有运行进程所以我不能为它们分配优先级:
Process process1 = new Process();
Process process2 = new Process();
Process process3 = new Process();
process1.StartInfo.FileName = "proc1";
process2.StartInfo.FileName = "proc2"'
process3.StartInfo.FileName = "proc3";
process1.PriorityClass = ProcessPriorityClass.AboveNormal;
process2.PriorityClass = ProcessPriorityClass.BelowNormal;
process3.PriorityClass = ProcessPriorityClass.High;
process2.Start();
process2.WaitForExit();
process1.Start();
process1.WaitForExit();
process3.Start();
答案 0 :(得分:1)
您可以使用进程文件名创建一个Dictionary,然后使用Linq查询通过ProcessPriorityClass和OrderBy对它们进行排序。然后你只需要执行它们迭代列表并使用值来分配正确的优先级。
public void StartProcessesByPriority(Dictionary<String, ProcessPriorityClass> values)
{
List<KeyValuePair<String, ProcessPriorityClass>> valuesList = values.ToList();
valuesList.Sort
(
delegate(KeyValuePair<String, ProcessPriorityClass> left, KeyValuePair<String, ProcessPriorityClass> right)
{
return left.Value.CompareTo(right.Value);
}
);
foreach (KeyValuePair<String, ProcessPriorityClass> pair in valuesList)
{
Process process = new Process();
process.StartInfo.FileName = pair.Key;
process.Start();
process.PriorityClass = pair.Value;
process.WaitForExit();
}
}