我正在为我的c ++课程制作日历程序,我只是想知道是否有办法改变程序中某些日子的颜色(例如,圣诞节,新年,周末,都会有不同的颜色)如果不可能,我至少可以大胆一点......
这是我的代码
char *month_name[12] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
char *month_underline[12] = {"-------", "--------", "-----", "-----", "---", "----", "----", "------", "---------", "-------", "--------", "--------"};
char *week_name[7] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};
int days = 1;
int days_max;
int i, j, k;
for(i = 0; i < 12; i++)
{
cout << "--------------------------------------------------------------------------------";
cout << '\n' << month_name[i] << '\n';
cout << month_underline[i] << "\n\n";
for (j = 0; j < 7; j++)
{
cout << week_name[j] << " ";
}
cout << "\n\n";
if (i == 0 || i == 2 || i == 4 || i == 6 || i == 7 || i == 9 || i == 11) //i is the number of the month minus 1 (jan = 0, feb = 1, etc.)
days_max = 32;
else if (i == 3 || i == 5 || i == 8 || i == 10)
days_max = 31;
else if (i == 1)
days_max = 29;
for (days = 1; days < days_max; days++)
{
if (i == 0 || i == 9)
{
if (days == 1)
{
cout << " ";
cout << setw(4) << days << " ";
}
else if (days == 6 || days == 13 || days == 20 || days == 27)
{
cout << "\n\n";
cout << setw(4) << days << " ";
}
else
cout << setw(4) << days << " ";
}
if (i == 1 || i == 2 || i == 10)
{
if (days == 1)
{
cout << " ";
cout << setw(4) << days << " ";
}
else if (days == 3 || days == 10 || days == 17 || days == 24 || days == 31)
{
cout << "\n\n";
cout << setw(4) << days << " ";
}
else
cout << setw(4) << days << " ";
}
if (i == 3 || i == 6)
{
if (days == 1)
{
cout << " ";
cout << setw(4) << days << " ";
}
else if (days == 7 || days == 14 || days == 21 || days == 28)
{
cout << "\n\n";
cout << setw(4) << days << " ";
}
else
cout << setw(4) << days << " ";
}
if (i == 4)
{
if (days == 1)
{
cout << " ";
cout << setw(4) << days << " ";
}
else if (days == 5 || days == 12 || days == 19 || days == 26)
{
cout << "\n\n";
cout << setw(4) << days << " ";
}
else
cout << setw(4) << days << " ";
}
if (i == 5)
{
if (days == 1)
{
cout << " ";
cout << setw(4) << days << " ";
}
else if (days == 2 || days == 9 || days == 16 || days == 23 || days == 30)
{
cout << "\n\n";
cout << setw(4) << days << " ";
}
else
cout << setw(4) << days << " ";
}
if (i == 7)
{
if (days == 1)
{
cout << " ";
cout << setw(4) << days << " ";
}
else if (days == 4 || days == 11 || days == 18 || days == 25)
{
cout << "\n\n";
cout << setw(4) << days << " ";
}
else
cout << setw(4) << days << " ";
}
if (i == 8 || i == 11)
{
if (days == 8 || days == 15 || days == 22 || days == 29)
{
cout << "\n\n";
cout << setw(4) << days << " ";
}
else
cout << setw(4) << days << " ";
}
}
cout << "\n";
}
cout << "--------------------------------------------------------------------------------";
system("PAUSE");
return EXIT_SUCCESS;
}
答案 0 :(得分:4)
在文本模式下,您有一些限制。但是有一些可移植的库可以处理你的目的,比如着色。
阅读此问题:Portable text based console manipulator并按照link进行操作。它至少可以在(Windows和ANSI-Escape支持的操作系统)之间移植
您可以更改以下代码的颜色:
#include <iostream>
#include "rlutil.h" // <-- Get it from the link
int main()
{
rlutil::setColor(2); // 2 for Green
std::cout << "Hello! I am green!" << std::endl;
return 0;
}
答案 1 :(得分:0)
没有C ++“标准”方法可以做到这一点。您可以按照Masoud的建议找到一个库 - 这将允许您的代码可移植到其他系统。或者您可以直接使用ANSI Escape序列[这可能是便携式解决方案在幕后所做的事情,但还有其他方法]。
此页面提供了一些信息: http://en.wikipedia.org/wiki/ANSI_escape_code
请记住,这是不可移植的,并不适用于所有平台。