Question

可能重复：
Sorting JavaScript Object by property value

我希望在我的JSON中获得一些值的最高结果。通过示例更容易解释：

var jsonData = {
  bom: [
        {
            "Component":"Some Thing",
            "Version":"Version ABC",
            "License":"License ABC",
        },
        {
            "Component":"Another Thing",
            "Version":"Version XYZ",
            "License":"License ABC",
        }, 
        etc ....
       ]
}

所以我的目标是确定“许可证ABC”或其他具有X次出现次数，然后我希望能够将这些键：val对排序到DOM中，因为“最受欢迎的X许可证是：

许可证ABC - 100
许可证XYZ - 70
许可证123 - 25

现在我有这个：

var countResults = function() {
    var fileLicenses = [];

    for ( var i = 0, arrLen = jsonData.files.length; i < arrLen; ++i ) {
        fileLicenses.push(jsonData.files[i]["License"]);
    }

    keyCount = {};
    for(i = 0; i < fileLicenses.length; ++i) {
        if(!keyCount[fileLicenses[i]]) {
            keyCount[fileLicenses[i]] = 0;
        }

        ++keyCount[fileLicenses[i]];
    }

    console.log( keyCount );
}();

这是我想要的最多的东西，一个带键的对象：值

{
    thisKey : 78,
    thatKey :125,
    another key : 200,
    another key : 272,
    another key : 45,
    etc ...
}

但我不知道怎么做。我只需要对数字右列进行排序，并让相关的键保持一致。思考？谢谢！

Answer 1

您无法按其值对对象进行排序。你可以做的是将它转换为一个对象数组并对其进行排序。类似的东西：

var rank = function(items, prop) {

  //declare a key->count table
  var results = {}

  //loop through all the items we were given to rank
  for(var i=0;len=items.length;i<len;i++) {

    //get the requested property value (example: License)
    var value = items[i][prop];

    //increment counter for this value (starting at 1)
    var count = (results[value] || 0) + 1;
    results[value] = count;
  }

  var ranked = []

  //loop through all the keys in the results object
  for(var key in results) {

    //here we check that the results object *actually* has
    //the key. because of prototypal inheritance in javascript there's
    //a chance that someone has modified the Object class prototype
    //with some extra properties. We don't want to include them in the
    //ranking, so we check the object has it's *own* property.
    if(results.hasOwnProperty(key)) {

      //add an object that looks like {value:"License ABC", count: 2} 
      //to the output array
      ranked.push({value:key, count:results[key]}); 
    }
  }

  //sort by count descending
  return ranked.sort(function(a, b) { return b.count - a.count; });
}

用法：

var sorted = rank(jsonData.bom, "License");
var first = sorted[0].value;

/代码未经过测试

Javascript - 计算重复的JSON值并将Count与关联键一起排序？

1 个答案: