Question

我有一张桌子programparticipants。我目前正在成功查询count(name) > 1的ID。我现在需要的是查询属于那些count(name) > 1。

的ID的名称

示例，当前返回的数据结果：

ID     count(name)
1      2
3      4
4      3

示例，需要数据结果：

ID     name
1      nm1
1      nm3
3      nm2
3      nm3
3      nm4
3      nm7
4      nm5
4      nm8
4      nm9

Answer 1

select count(id), name 
from programparticipants 
group by name 
having count(id) > 1

Answer 2

你可以用这个：

SELECT 
   (SELECT name FROM participants WHERE id=p.participantid) AS name
FROM
   programparticipants AS p
WHERE
   .... (the part where you find count(name)>1)

Answer 3

我认为GROUP BY and HAVING就是你想要的。

Answer 4

select id, Name 
from programparticipants
where id in ( <your current query selecting only id here> )

Answer 5

认为你想看看分组：

select id, name, count(name) from table group by 2,1 having count(name) = 2;

您可以将= 2替换为＆gt; 1取决于你想要的任何东西（标题说= 2，问题说＆gt; 1）

Answer 6

SELECT id, Name
FROM   programparticipants
GROUP BY id, Name
HAVING COUNT(*) > 1

SQL查询需要获取count（id）= 2的名称

6 个答案: