Question

可能重复：
Mysql rank function

我有以下countryTable

country  clicks
-------  ------
0        222
66       34 
175      1000
45       650

如何获得说国45的排名，在这种情况下为2？

Answer 1

由country ASC订购：

SELECT 1+COUNT(*) AS ranking
FROM countryTable
WHERE country < 45 ;

由clicks DESC订购：

SELECT 1+COUNT(*) AS ranking
FROM countryTable AS t
  JOIN countryTable AS c
      ON c.clicks > t.clicks
WHERE t.country = 45 ;

Answer 2

你可以获得如下所示的2级排名：

Select * from tabeName order by clicks limit 1,1

3级：

Select * from tabeName order by clicks limit 2,1

Answer 3

SELECT *
FROM 
(
  SELECT  @ranking:= @ranking + 1 rank,
          a.country,
          a.clicks
  FROM    tableName a, (SELECT @ranking := 0) b
  ORDER BY a.clicks DESC
) s
WHERE country = 45

SQLFiddle Demo

Answer 4

这将显示国家/地区45的正确等级（2）。您没有指定如何对关系进行排名，因此您可能希望更改比较以适合您。不存在的国家排名为0.

SELECT COUNT(*) rank 
FROM countryTable a
JOIN countryTable b
  ON a.clicks <= b.clicks
WHERE a.country = 45

SQLfiddle here

Answer 5

X是您需要查找的排名：

SELECT * FROM T ORDER BY clicks DESC LIMIT X-1,1

Answer 6

这是另一种（惊人的快速）方式（尽管限制为256行）：

SELECT country
     , clicks
     , FIND_IN_SET(clicks,(SELECT GROUP_CONCAT(DISTINCT clicks ORDER BY clicks DESC) FROM country_clicks)) rank
FROM country_clicks

或者，如果您愿意......

SELECT FIND_IN_SET(clicks,(SELECT GROUP_CONCAT(DISTINCT clicks ORDER BY clicks DESC) FROM country_clicks)) rank
   FROM country_clicks
  WHERE country = 45;

在mysql中找到整数的排名

6 个答案: