使用Python从Gmail中提取信息

时间:2013-01-12 14:04:11

标签: python gmail extract imaplib

我已经通过解决方案从Gmail邮箱中选定的已接收电子邮件中提取有用信息

此示例的目的是获取从提供石油月度价格的简报发送的所有邮件。您可以在EIA网站上自由订阅此类时事通讯。所有这些时事通讯都会在我的Gmail邮箱中的相同文件夹中找到,并以“$”开头。

电子邮件的内容就是那样

enter image description here

我的目标是编写一个脚本来获取最后10封这样的电子邮件(过去10个月),并根据时间绘制不同美国地区的石油价格。

1 个答案:

答案 0 :(得分:20)

Python email库会有所帮助。

import email, getpass, imaplib, os, re
import matplotlib.pyplot as plt

此目录是您保存附件的地方

 detach_dir = "F:\OTHERS\CS\PYTHONPROJECTS"  

然后,您的脚本会向用户(或您自己)询问帐户功能

user = raw_input("Enter your GMail username --> ")
pwd = getpass.getpass("Enter your password --> ")

然后连接到gmail imap服务器并登录

m = imaplib.IMAP4_SSL("imap.gmail.com")
m.login(user, pwd)

选择一个文件夹,您可以使用整个INBOX

m.select("BUSINESS/PETROLEUM")    

应该使用m.list()来获取所有邮箱。搜索来自指定发件人和的所有电子邮件 选择邮件ID:

resp, items = m.search(None, '(FROM "EIA_eLists@eia.gov")')
items = items[0].split()  

my_msg = [] # store relevant msgs here in please
msg_cnt = 0
break_ = False

我想要最后的电子邮件,以便我使用items[::-1]

for emailid in items[::-1]:

    resp, data = m.fetch(emailid, "(RFC822)")

    if ( break_ ):
        break

    for response_part in data:

      if isinstance(response_part, tuple):
          msg = email.message_from_string(response_part[1])
          varSubject = msg['subject']
          varDate = msg['date']

我只想要以$

开头的那些
          if varSubject[0] == '$':
              r, d = m.fetch(emailid, "(UID BODY[TEXT])")

              ymd = email.utils.parsedate(varDate)[0:3]
              my_msg.append([ email.message_from_string(d[0][1]) , ymd ])

              msg_cnt += 1

我只想要N = 100张最后消息

              if ( msg_cnt == 100 ):
                  break_ = True

l = len(my_msg)
US, EastCst, NewEng, CenAtl, LwrAtl, Midwst, GulfCst, RkyMt, WCst, CA = 
[0]*l, [0]*l, [0]*l, [0]*l, [0]*l, [0]*l, [0]*l, [0]*l, [0]*l, [0]*l 
absc = [k for k in range(len(my_msg))]
dates = [str(msg[1][2])+'-'+str(msg[1][3])+'-'+str(msg[1][0]) for msg in my_msg]
cnt = -1

for msg in my_msg:

    data = str(msg[0]).split("\n")
    cnt+=1
    for c in [k.split("\r")[0] for k in data[2:-2]]: 

使用正则表达式获取相关信息

        m = re.match( r"(.+)(=3D\$)(.+)" , c )  
        if( m == None ):
            continue 

        country, na, price = m.groups()

        if ( country == "US" or country == "USA" ) :
            US[cnt] = float(price)
        elif( country == "NewEng" ) :
            EastCst[cnt] = float(price)    
        elif( country == "EastCst" ) :
            NewEng[cnt] = float(price)  
        elif( country == "EastCst" ) :
            CenAtl[cnt] = float(price) 
        elif( country == "EastCst" ) :
            LwrAtl[cnt] = float(price)
        elif( country == "EastCst" ) :
            Midwst[cnt] = float(price)
        elif( country == "EastCst" ) :
            GulfCst[cnt] = float(price)
        elif( country == "EastCst" ) :
            RkyMt[cnt] = float(price)
        elif( country == "EastCst" ) :
            WCst[cnt] = float(price)
        elif( country == "EastCst" ) :
            CA[cnt] = float(price)

用美国价格绘制所有这些曲线

plt.plot( absc, US )

plt.plot( absc, EastCst )    
plt.plot( absc, NewEng, '#251BE0' )    
plt.plot( absc, EastCst, '#1BE0BF' )
plt.plot( absc, CenAtl, '#E0771B' )
plt.plot( absc, LwrAtl, '#CC1BE0' )
plt.plot( absc, Midwst, '#E01B8B' ) 
plt.plot( absc, GulfCst, '#E01B3F' )
plt.plot( absc, RkyMt )
plt.plot( absc, WCst )
plt.plot( absc, CA )

plt.legend( ('US', 'EastCst', 'NewEng' , 'EastCst', 'CenAtl', 'LwrAtl', 'Midwst', 'GulfCst', 'RkyMt', 'WCst', 'CA')  )
plt.title('Diesel price')
locs,labels = plt.xticks(absc, dates)
plt.show()

一些相关的有趣话题在这里

Get only new emails

Fetch mail body

Forward emails with attachment

Fetch body emails in gmail

结果仅限于三个区域

us prices