我正在使用以下编码来获取字符串格式的名字,但是想要在数组中获取它,因为它包括地址簿联系人和Facebook联系人。所以我可以像array [0],array [1]那样快速检索它们。所以请帮助我完成这项工作。
ABAddressBookRef ab=ABAddressBookCreate();
NSArray *arrTemp=(NSArray *)ABAddressBookCopyArrayOfAllPeople(ab);
NSMutableArray *arrContact=[[NSMutableArray alloc] init];
for (int i=0;i<[arrTemp count];i++)
{
NSMutableDictionary *dicContact=[[NSMutableDictionary alloc] init];
NSString *str=(NSString *) ABRecordCopyValue([arrTemp objectAtIndex:i], kABPersonFirstNameProperty);
@try
{
[dicContact setObject:str forKey:@"name"];
}
@catch (NSException * e) {
[dicContact release];
continue;
}
[dicContact release];
NSLog(@"%@",str );
答案 0 :(得分:1)
您可以存储您的地址将所有联系人保存到NSMutableArray中,如下所示: -
ABAddressBookRef addressBook = ABAddressBookCreate();
NSArray *thePeople = (NSArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);
NSMutableArray* allPeoplesDicts = [NSMutableArray array];
for (id person in thePeople)
{
ABMultiValueRef phones =(NSString*)ABRecordCopyValue(person, kABPersonPhoneProperty);
NSString* name = (NSString *)ABRecordCopyCompositeName(person);
NSMutableArray* phones = [[NSMutableArray alloc] init];
for (CFIndex i = 0; i < ABMultiValueGetCount(phones); i++)
{
NSString *phone = [(NSString *)ABMultiValueCopyValueAtIndex(phones,i) autorelease];
[phones addObject:phone];
}
NSDictionary* personDict = [[NSDictionary alloc] initWithObjectsAndKeys:name,@"Name",phones,@"PhoneNumbers",nil];
[phones release];
[allPeoplesDicts addObject:personDict];
[personDict release];
}
我只是谷歌它,我访问了这个类似的问题: -