我有一个php登录系统，但缺乏功能。我想在用户登录前向用户发送电子邮件地址，他们必须点击链接激活帐户。我也想让他们需要新的密码，以防他们忘记了他们的密码......除了这两个问题，其他一切正常。我是否实现了这一目标？感谢
我在数据库中的表users中拥有的内容：
1 id int(11) AUTO_INCREMENT
2 username varchar(255)
3 password char(64)
4 salt char(16)
5 email varchar(255)
register.php
// First we execute our common code to connection to the database and start the session
require("common.php");
// This if statement checks to determine whether the registration form has been submitted
// If it has, then the registration code is run, otherwise the form is displayed
if(!empty($_POST))
{
// Ensure that the user has entered a non-empty username
if(empty($_POST['username']))
{
echo "Please enter a username.";
}
// Ensure that the user has entered a non-empty password
if(empty($_POST['password']))
{
die("Please enter a password.");
}
// Make sure the user entered a valid E-Mail address
// filter_var is a useful PHP function for validating form input, see:
if(!filter_var($_POST['email'], FILTER_VALIDATE_EMAIL))
{
die("Invalid E-Mail Address");
}
$query = "
SELECT
1
FROM users
WHERE
username = :username
";
$query_params = array(
':username' => $_POST['username']
);
try
{
// These two statements run the query against your database table.
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch(PDOException $ex)
{
// Note: On a production website, you should not output $ex->getMessage().
// It may provide an attacker with helpful information about your code.
die("Failed to run query: " . $ex->getMessage());
}
$row = $stmt->fetch();
if($row)
{
die("This username is already in use");
}
// Now we perform the same type of check for the email address, in order
// to ensure that it is unique.
$query = "
SELECT
1
FROM users
WHERE
email = :email
";
$query_params = array(
':email' => $_POST['email']
);
try
{
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch(PDOException $ex)
{
die("Failed to run query: " . $ex->getMessage());
}
$row = $stmt->fetch();
if($row)
{
die("This email address is already registered");
}
// An INSERT query is used to add new rows to a database table.
// Again, we are using special tokens (technically called parameters) to
// protect against SQL injection attacks.
$query = "
INSERT INTO users (
username,
password,
salt,
email
) VALUES (
:username,
:password,
:salt,
:email
)
";
$salt = dechex(mt_rand(0, 2147483647)) . dechex(mt_rand(0, 2147483647));
$password = hash('sha256', $_POST['password'] . $salt);
for($round = 0; $round < 65536; $round++)
{
$password = hash('sha256', $password . $salt);
}
$query_params = array(
':username' => $_POST['username'],
':password' => $password,
':salt' => $salt,
':email' => $_POST['email']
);
try
{
// Execute the query to create the user
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch(PDOException $ex)
{
}
header("Location: login.php");
die("Redirecting to login.php");
}
?>
<h1>Register</h1>
<form action="" method="post">
Username:<br />
<input type="text" name="username" required value="" />
<br /><br />
E-Mail:<br />
<input type="text" name="email" required value="" />
<br /><br />
Password:<br />
<input type="password" required name="password" value="" />
<br /><br />
<input type="submit" value="Register" />
</form>
的login.php
<?php
// First we execute our common code to connection to the database and start the session
require("common.php");
$submitted_username = '';
if(!empty($_POST))
{
$query = "
SELECT
id,
username,
password,
salt,
email
FROM users
WHERE
username = :username
";
// The parameter values
$query_params = array(
':username' => $_POST['username']
);
try
{
// Execute the query against the database
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch(PDOException $ex)
{
die("Failed to run query: " . $ex->getMessage());
}
$login_ok = false;
$row = $stmt->fetch();
if($row)
{
$check_password = hash('sha256', $_POST['password'] . $row['salt']);
for($round = 0; $round < 65536; $round++)
{
$check_password = hash('sha256', $check_password . $row['salt']);
}
if($check_password === $row['password'])
{
$login_ok = true;
}
}
if($login_ok)
{
unset($row['salt']);
unset($row['password']);
$_SESSION['user'] = $row;
// Redirect the user to the private members-only page.
header("Location: private.php");
die("Redirecting to: private.php");
}
else
{
// Tell the user they failed
print("The Username/Password is invalid.");
$submitted_username = htmlentities($_POST['username'], ENT_QUOTES, 'UTF-8');
}
}
?>
<h1>Login</h1>
<form action="login.php" method="post">
Username:<br />
<input type="text" name="username" required value="<?php echo $submitted_username; ?>" />
<br /><br />
Password:<br />
<input type="password" name="password" value="" required />
<br /><br />
<input type="submit" value="Login" />
</form>
<a href="register.php">Register</a>
答案 0 :(得分：3)
一般来说，要验证电子邮件，您需要做的是在注册时创建一个随机字符串;并使用新注册的用户ID或电子邮件地址将该字符串存储在数据库中。然后在您的电子邮件中，您发送一个附加了该字符串的链接。 EX：
<a href="http://www.mywebsite.com/activate.php?v=329857320952">Activate your account now</a>
然后，当他们转到该链接时，您使用$ _GET ['v']从链接获取该值并检查您的数据库...然后您在数据库中搜索该特定值并编辑/删除该行用户与该值相关联。
然后，在此过程中，您将有两种方法可以让用户注册。您可以将列周长值设置为“已注册”或“1”或几乎任何内容;或者您可以删除具有该存储的注册值的行...
这意味着每次用户登录时，您需要检查该新列值，或者该用户是否存在于'not_activated_yet'表中。有很多方法可以做到这一点，但这是一个非常基本的程序。
以下是一些可以帮助您的基本脚本...... 在用户满足您将数据放入数据库的php附近的所有注册要求后，您可以使用它向他们发送电子邮件...
<?php
$to = "$user_email";
$subject = "Your Account Information!";
$body = <<<EMAIL
Hello {$user_firstname} {$user_lastname}, here is your account information!
Username:{$user_username}
Password:{$user_pass}
Please activate your account by clicking the following activation link:
http://www.mywebsite.com/activate.php?aid={$aid}
EMAIL;
$headers = 'From: notify@yourwebsite.com' . "\r\n" .
'Reply-To: notify@yourwebsite.com' . "\r\n" .
'X-Mailer: PHP/' . phpversion();
if (mail($to, $subject, $body, $headers)) {
echo("<p>Your account information was successfully sent to your email - ($user_email)!<br><br>Please open your email and click the activation link to activate your account.</p><br><p>If you do not see your account information in your inbox within 60 seconds please check your spam/junk folder.</p>");
} else {
echo("<p> Unfortunately, your account information was <u>unsuccessfully</u> sent to your email - ($user_email).</p>");
}
?>
至于更改密码，有两种不同的情况。一个是他们知道他们的旧密码，只是想改变它...这就像有一个表单，他们输入他们的电子邮件，oldpassword和newpassword ...你检查在你的数据库中输入的密码和电子邮件是否使用相同的行...如果这是真的，您只需运行UPDATE查询以使用新的更新其密码字段...
对于密码重置最简单的方法可能是在登录页面上某处说忘了密码？使用链接将其重定向到他们输入电子邮件的页面;就像注册一样，你给他们发了一封电子邮件。然后存储唯一密钥和用户ID ...一旦在该链接上，他们输入一个新密码;您可以在其中找到存储用户id和临时密钥的表;然后更新该用户ID的表密码。
编辑：此外，如果您想要而不是所有设置临时密钥，您只需将电子邮件发送到密码，但假设您的数据库中的密码已加密，您将不得不使用临时密钥。
忘记密码相关代码（第1部分发送）：
<?php
if(isset($_POST['submit'])){
$email = $_POST['email'];
//generate a random string
/// insert the key and email into a row in some table of your choosing.
///send email to the email address with the code above.
///echo success so the user knows everything worked.
}
?>
<form action='' method='POST>
<input type='text' name='pass'>
<input type='submit' name='submit' value='Send Password Request'>
</form>
第2部分处理：
<?php
$key = $_GET['key']; //gets key from the link you sent in your e-mail; what temporarily connects to that user.
// search your database table for that key
// once you have that users id delete the row in the password-request table and insert the password into your users table row.
?>
答案 1 :(得分：0)
只需在users表中添加2个字段，表示令牌和状态。现在创建一个链接，在最后添加此令牌（http://yourdomain.com/users/accountactivation/34gg456sas78ud）并通过电子邮件发送。当用户点击此链接时，控件将转到帐户激活，其中运行查询以验证数据库中是否存在此令牌。如果是，请将该用户的状态更改为1，并同时更改/删除表中的令牌，以使链接过期。当用户登录时，检查用户状态是否为1.如果是，用户可以登录，否则会显示一条消息以检查电子邮件以激活帐户。