Question

我基本上是在mySQL查询期间尝试两次使用NOT IN函数我的新当前查询如下

SELECT `o`.`id`, `o`.`name`, `o`.`url`, `o`.`type`, `o`.`desc` FROM `offers` as `o` 
WHERE `o`.country_iso = '$country_iso' AND `o`.`id` not in 
(select distinct(offer_id) from conversions where ip = '$_SERVER[REMOTE_ADDR]' 
and converted != '0') AND `o`.`id` not in 
(select `offer_id` from `aff_disabled_offers` where `offer_id` = 'o.id' 
and `user_id` = '1') ORDER by rand() LIMIT $limit

查询有效但由于某种原因它完全忽略了这个

AND `o`.`id` not in 
(select `offer_id` from `aff_disabled_offers` where `offer_id` = 'o.id')

Answer 1

您需要在条件之间指定运算符，例如AND或OR。您还需要在NOT IN子句中有效查询。

SELECT `o`.`id`, `o`.`name`, `o`.`url`, `o`.`type`, `o`.`desc` 
FROM `offers` as `o` 
WHERE `o`.country_iso = '$country_iso' 
AND `o`.`id` not in (select distinct(offer_id)
                     from converstions where
                     from conversions 
                     where ip = '$_SERVER[REMOTE_ADDR]' 
                     and converted != '0')
AND `o`.`somevar` not in (select `somevar` from 
                          `sometable` where `offer_id` = 'o.id')
ORDER by rand() LIMIT 0,6

mySQL“不在”查询中抛出错误

1 个答案: