我想仅使用带有svg / canvas和js maximum的css来逐行绘制线条。可以找到我想要绘制的线条的想法here
<svg width="640" height="480" xmlns="http://www.w3.org/2000/svg">
<!-- Created with SVG-edit - http://svg-edit.googlecode.com/ -->
<g>
<title>Layer 1</title>
<path d="m33,104c1,0 2.1306,-0.8037 23,3c9.07012,1.65314 10,2 24,2c7,0 29,0 33,0c8,0 9,0 11,0c2,0 8,0 11,0c9,0 17,0 18,0c10,0 12,0 20,0c1,0 6,0 7,0c2,0 3.07613,0.38268 4,0c2.61313,-1.08239 2,-3 2,-6c0,-1 0,-2 0,-3c0,-1 0,-2 0,-3c0,-1 0,-2 0,-3c0,-1 0.30745,-3.186 -1,-5c-0.8269,-1.14727 -0.09789,-2.82443 -2,-4c-0.85065,-0.52573 -2.82443,-0.09789 -4,-2c-0.52573,-0.85065 -2.58578,-0.58578 -4,-2c-0.70711,-0.70711 -1.81265,-1.20681 -4,-3c-2.78833,-2.28588 -3.64749,-2.97251 -8,-4c-2.91975,-0.68926 -4.82375,-2.48626 -7,-3c-2.91975,-0.68926 -5.15224,-0.23463 -7,-1c-1.30656,-0.5412 -4.38687,-1.91761 -7,-3c-1.84776,-0.76537 -5.03609,0.37821 -7,0c-5.28799,-1.01837 -8,-3 -9,-3c-2,0 -5.0535,-0.54049 -7,-1c-2.17625,-0.51374 -4.15224,-0.23463 -6,-1c-1.30656,-0.54119 -3,-1 -4,-1c-2,0 -5,-1 -6,-1c-1,0 -3,-2 -6,-2c-2,0 -5,-2 -6,-2c-2,0 -2.02583,-0.67963 -4,-1c-3.12144,-0.50654 -4.15224,-0.23463 -6,-1c-1.30656,-0.54119 -2,-1 -3,-1c-2,0 -3,0 -5,0c-1,0 -2,0 -3,0c-1,0 -2,0 -3,0c-1,0 -2,0 -3,0c-2,0 -3.85273,0.1731 -5,1c-1.81399,1.30745 -5.18601,1.69255 -7,3c-1.14727,0.8269 -1.82375,2.48626 -4,3c-0.97325,0.22975 -1.69344,1.45881 -3,2c-0.92388,0.38268 -1.45951,1.0535 -1,3c0.51374,2.17625 3.07844,2.78985 6,4c2.06586,0.85571 3.38688,1.91761 6,3c1.84776,0.76537 5.2987,-1.05146 7,0c1.90211,1.17557 3.82375,2.48626 6,3c0.97325,0.22975 3.29289,0.29289 4,1c0.70711,0.70711 4,2 9,4c5,2 8,4 11,4c2,0 5,0 7,0c3,0 5,0 7,0c2,0 4,0 7,0c2,0 4,0 8,0c3,0 7,0 10,0c4,0 7,0 12,0c3,0 5,0 6,0c2,0 3,0 5,0c1,0 1.09789,-0.82443 3,-2c0.85065,-0.52573 3.07613,0.38268 4,0c1.30656,-0.5412 0.71022,-2.04291 1,-3c1.04483,-3.45084 2.84723,-5.04132 4,-9c0.88414,-3.03616 1.85194,-5.22836 3,-8c0.5412,-1.30656 1.5405,-2.0535 2,-4c0.51375,-2.17625 2.71413,-4.21167 5,-7c2.68979,-3.28101 4,-6 5,-7c1,-1 2,-2 2,-4c0,-1 0.70711,-2.29289 0,-3c-0.70711,-0.70711 -2.07613,0.38268 -3,0c-1.30656,-0.54119 -2,-1 -4,-1c-3,0 -6.87856,-2.49346 -10,-3c-2.96126,-0.48055 -6.71201,-0.98162 -12,-2c-2.94586,-0.56732 -5,-1 -9,-1c-3,0 -6,-1 -8,-1c-2,0 -5,-3 -7,-3c-2,0 -5.38687,-0.91761 -8,-2c-0.92388,-0.38268 -3.0535,-0.54049 -5,-1c-2.17625,-0.51374 -4.58578,0.41421 -6,-1c-0.70711,-0.70711 -1,-1 -2,-1c-1,0 -2,0 -3,0c-1,0 -2,0 -4,0c-1,0 -2,0 -3,0c-1,0 -2,0 -4,0c-1,0 -2,0 -3,0c-2,0 -3,0 -5,0c-1,0 -2,0 -3,0c-1,0 -3,0 -4,0c-3,0 -5,0 -7,0c-2,0 -4,0 -6,0c-2,0 -3,0 -5,0c-1,0 -2,0 -3,0c-2,0 -4,0 -5,0c-1,0 -2,0 -4,0c-1,0 -2,0 -3,1l-1,0" id="svg_1" stroke-width="5" stroke="#000000" fill="none"/>
</g>
</svg>
答案 0 :(得分:37)
此答案中列出了三种技术:
有一个全SVG解决方案,涉及逐步修改形状的stroke-dasharray
以绘制更长更长的“破折号”,然后是巨大的间隙。
相关代码:
var distancePerPoint = 1;
var drawFPS = 60;
var orig = document.querySelector('path'), length, timer;
orig.addEventListener('mouseover',startDrawingPath,false);
orig.addEventListener('mouseout', stopDrawingPath, false);
function startDrawingPath(){
length = 0;
orig.style.stroke = '#f60';
timer = setInterval(increaseLength,1000/drawFPS);
}
function increaseLength(){
var pathLength = orig.getTotalLength();
length += distancePerPoint;
orig.style.strokeDasharray = [length,pathLength].join(' ');
if (length >= pathLength) clearInterval(timer);
}
function stopDrawingPath(){
clearInterval(timer);
orig.style.stroke = '';
orig.style.strokeDasharray = '';
}
或者,您仍然可以使用所有SVG并选择一次构建一个SVG路径:
相关代码:
// Assumes 'orig' and dup' are SVG paths
function addNextPathSegment(){
var nextIndex = dup.pathSegList.numberOfItems;
if (nextIndex<orig.pathSegList.numberOfItems){
var nextSegment = orig.pathSegList.getItem(nextIndex);
var segmentDup = cloneSVGPathSeg( dup, nextSegment );
dup.pathSegList.appendItem( segmentDup );
}
}
function cloneSVGPathSeg( path, seg ){
switch(seg.pathSegTypeAsLetter){
case 'M': return path.createSVGPathSegMovetoAbs(seg.x,seg.y); break;
case 'm': return path.createSVGPathSegMovetoRel(seg.x,seg.y); break;
case 'L': return path.createSVGPathSegLinetoAbs(seg.x,seg.y); break;
case 'l': return path.createSVGPathSegLinetoRel(seg.x,seg.y); break;
case 'H': return path.createSVGPathSegLinetoHorizontalAbs(seg.x); break;
case 'h': return path.createSVGPathSegLinetoHorizontalRel(seg.x); break;
case 'V': return path.createSVGPathSegLinetoVerticalAbs(seg.y); break;
case 'v': return path.createSVGPathSegLinetoVerticalRel(seg.y); break;
case 'C': return path.createSVGPathSegCurvetoCubicAbs(seg.x,seg.y,seg.x1,seg.y1,seg.x2,seg.y2); break;
case 'c': return path.createSVGPathSegCurvetoCubicRel(seg.x,seg.y,seg.x1,seg.y1,seg.x2,seg.y2); break;
case 'S': return path.createSVGPathSegCurvetoCubicSmoothAbs(seg.x,seg.y,seg.x2,seg.y2); break;
case 's': return path.createSVGPathSegCurvetoCubicSmoothRel(seg.x,seg.y,seg.x2,seg.y2); break;
case 'Q': return path.createSVGPathSegCurvetoQuadraticAbs(seg.x,seg.y,seg.x1,seg.y1); break;
case 'q': return path.createSVGPathSegCurvetoQuadraticRel(seg.x,seg.y,seg.x1,seg.y1); break;
case 'T': return path.createSVGPathSegCurvetoQuadraticSmoothAbs(seg.x,seg.y); break;
case 't': return path.createSVGPathSegCurvetoQuadraticSmoothRel(seg.x,seg.y); break;
case 'A': return path.createSVGPathSegArcAbs(seg.x,seg.y,seg.r1,seg.r2,seg.angle,seg.largeArcFlag,seg.sweepFlag); break;
case 'a': return path.createSVGPathSegArcRel(seg.x,seg.y,seg.r1,seg.r2,seg.angle,seg.largeArcFlag,seg.sweepFlag); break;
case 'z':
case 'Z': return path.createSVGPathSegClosePath(); break;
}
}
最后,您可以选择通过定期对SVG路径进行采样并绘制到画布来绘制HTML5画布的路径。 (请注意,为此不需要显示SVG路径;您可以完全使用JavaScript构建SVG路径元素并对其进行采样):
相关代码:
function startDrawingPath(){
points = [];
timer = setInterval(buildPath,1000/drawFPS);
}
// Assumes that 'orig' is an SVG path
function buildPath(){
var nextPoint = points.length * distancePerPoint;
var pathLength = orig.getTotalLength();
if (nextPoint <= pathLength){
points.push(orig.getPointAtLength(nextPoint));
redrawCanvas();
} else stopDrawingPath();
}
function redrawCanvas(){
clearCanvas();
ctx.beginPath();
ctx.moveTo(points[0].x,points[0].y);
for (var i=1;i<points.length;i++) ctx.lineTo(points[i].x,points[i].y);
ctx.stroke();
}
答案 1 :(得分:6)
所以有类似的问题with this answer。
我走了你的路径并将其放入答案的代码中。
HTML:
<html>
<style>
#canvas
{
border-style:solid;
border-width:1px;
}
</style>
<div id="canvas">
<p>Hover over me</p>
</div>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
Javascript (请注意,示例中使用了Jquery 1.8.3和Raphael 1.5.2):
$(function() {
animateLine = function(canvas, hoverDivName, colorNumber, pathString) {
$('#' + hoverDivName).hover(
function() {
var line = canvas.path(pathString).attr({
stroke: colorNumber
});
var length = line.getTotalLength();
$('path[fill*="none"]').animate({
'to': 1
}, {
duration: 5000,
step: function(pos, fx) {
var offset = length * fx.pos;
var subpath = line.getSubpath(0, offset);
canvas.clear();
canvas.path(subpath).attr({
'stroke-width': 5,
stroke: colorNumber
});
},
});
}, function() {
$('path[fill*="none"]').stop(true, false).fadeOut();
});
};
var canvas = Raphael('canvas', 200, 200);
var pathString = "m33,104c1,0 2.1306,-0.8037 23,3c9.07012,1.65314 10,2 24,2c7,0 29,0 33,0c8,0 9,0 11,0c2,0 8,0 11,0c9,0 17,0 18,0c10,0 12,0 20,0c1,0 6,0 7,0c2,0 3.07613,0.38268 4,0c2.61313,-1.08239 2,-3 2,-6c0,-1 0,-2 0,-3c0,-1 0,-2 0,-3c0,-1 0,-2 0,-3c0,-1 0.30745,-3.186 -1,-5c-0.8269,-1.14727 -0.09789,-2.82443 -2,-4c-0.85065,-0.52573 -2.82443,-0.09789 -4,-2c-0.52573,-0.85065 -2.58578,-0.58578 -4,-2c-0.70711,-0.70711 -1.81265,-1.20681 -4,-3c-2.78833,-2.28588 -3.64749,-2.97251 -8,-4c-2.91975,-0.68926 -4.82375,-2.48626 -7,-3c-2.91975,-0.68926 -5.15224,-0.23463 -7,-1c-1.30656,-0.5412 -4.38687,-1.91761 -7,-3c-1.84776,-0.76537 -5.03609,0.37821 -7,0c-5.28799,-1.01837 -8,-3 -9,-3c-2,0 -5.0535,-0.54049 -7,-1c-2.17625,-0.51374 -4.15224,-0.23463 -6,-1c-1.30656,-0.54119 -3,-1 -4,-1c-2,0 -5,-1 -6,-1c-1,0 -3,-2 -6,-2c-2,0 -5,-2 -6,-2c-2,0 -2.02583,-0.67963 -4,-1c-3.12144,-0.50654 -4.15224,-0.23463 -6,-1c-1.30656,-0.54119 -2,-1 -3,-1c-2,0 -3,0 -5,0c-1,0 -2,0 -3,0c-1,0 -2,0 -3,0c-1,0 -2,0 -3,0c-2,0 -3.85273,0.1731 -5,1c-1.81399,1.30745 -5.18601,1.69255 -7,3c-1.14727,0.8269 -1.82375,2.48626 -4,3c-0.97325,0.22975 -1.69344,1.45881 -3,2c-0.92388,0.38268 -1.45951,1.0535 -1,3c0.51374,2.17625 3.07844,2.78985 6,4c2.06586,0.85571 3.38688,1.91761 6,3c1.84776,0.76537 5.2987,-1.05146 7,0c1.90211,1.17557 3.82375,2.48626 6,3c0.97325,0.22975 3.29289,0.29289 4,1c0.70711,0.70711 4,2 9,4c5,2 8,4 11,4c2,0 5,0 7,0c3,0 5,0 7,0c2,0 4,0 7,0c2,0 4,0 8,0c3,0 7,0 10,0c4,0 7,0 12,0c3,0 5,0 6,0c2,0 3,0 5,0c1,0 1.09789,-0.82443 3,-2c0.85065,-0.52573 3.07613,0.38268 4,0c1.30656,-0.5412 0.71022,-2.04291 1,-3c1.04483,-3.45084 2.84723,-5.04132 4,-9c0.88414,-3.03616 1.85194,-5.22836 3,-8c0.5412,-1.30656 1.5405,-2.0535 2,-4c0.51375,-2.17625 2.71413,-4.21167 5,-7c2.68979,-3.28101 4,-6 5,-7c1,-1 2,-2 2,-4c0,-1 0.70711,-2.29289 0,-3c-0.70711,-0.70711 -2.07613,0.38268 -3,0c-1.30656,-0.54119 -2,-1 -4,-1c-3,0 -6.87856,-2.49346 -10,-3c-2.96126,-0.48055 -6.71201,-0.98162 -12,-2c-2.94586,-0.56732 -5,-1 -9,-1c-3,0 -6,-1 -8,-1c-2,0 -5,-3 -7,-3c-2,0 -5.38687,-0.91761 -8,-2c-0.92388,-0.38268 -3.0535,-0.54049 -5,-1c-2.17625,-0.51374 -4.58578,0.41421 -6,-1c-0.70711,-0.70711 -1,-1 -2,-1c-1,0 -2,0 -3,0c-1,0 -2,0 -4,0c-1,0 -2,0 -3,0c-1,0 -2,0 -4,0c-1,0 -2,0 -3,0c-2,0 -3,0 -5,0c-1,0 -2,0 -3,0c-1,0 -3,0 -4,0c-3,0 -5,0 -7,0c-2,0 -4,0 -6,0c-2,0 -3,0 -5,0c-1,0 -2,0 -3,0c-2,0 -4,0 -5,0c-1,0 -2,0 -4,0c-1,0 -2,0 -3,1l-1,0";
animateLine(canvas, "canvas", "#000", pathString);
});
d
]属性中获取了您的路径并将其放在pathString
变量中。stroke-width
] 我只用了一次非常短暂的raphael,但查看示例并查看代码是如何构建的(from page source
)让你走得很远(我不记得怎么样/放置stroke-width
的位置,因此我从此example的页面源检查了该方法。)。
You can find raphael + more info from here.
只是为了好玩,I made my own path...
答案 2 :(得分:4)
使用Phrogz优秀技术我使用TweenLite创建了一个非常基本的GreenSock动画,将长度值补间为getTotalLength()值。
正如您在演示中所看到的,将其挂钩到补间引擎可以提供大量的控制,并且只需要很少的代码。
var orig = document.querySelector('path'), length, timer;
var obj = {length:0,
pathLength:orig.getTotalLength()};
orig.style.stroke = '#f60';
var t = TweenMax.to(obj, 10, {length:obj.pathLength, onUpdate:drawLine, ease:Linear.easeNone})
function drawLine() {
orig.style.strokeDasharray = [obj.length,obj.pathLength].join(' ');
updateSlider();
}
非常尊重Phrogz这个令人敬畏的想法和代码。
答案 3 :(得分:1)
http://www.ashleysheridan.co.uk/coding/javascript/Animated+Glowing+Line+Drawing+in+Canvas