Question

下面我展示了用于显示表格行的PHP代码，如果表selected_val中selected_candidate为1，如何突出显示行？

下面我展示了我正在使用的查询和if / else循环。我收到以下警告：'警告：mysql_fetch_array（）：提供的参数不是有效的MySQL结果资源'。

<?php

    if(isset($_POST['Submit']))
    {
        $i=0;
        while($data_set = mysql_fetch_array($result_set))
        {
            $i=0;
            echo "<div id=\"Message1[$i]\" class=\"box\">";
            echo "Country ={$data_set['ecountry']}<br/>";
            echo "State = {$data_set['estate']}<br/>";
            echo "</div>";
            echo "<tr>";
            echo "<td><input id=\"select_candi{$i}\" onclick=\"javascript:func(this.id,{$_SESSION['uid']})\" type=\"checkbox\" name=\"check_candi[]\" value=\"{$data_set['eid']}\"/></td>"; 
            echo "<td>{$data_set['ename']}</td>";
            echo "<td>{$data_set['lname']}</td>";
            echo "<td>{$data_set['ecell']}</td>";
            echo "<td>{$data_set['eposition']}</td>";
            echo "<td>{$data_set['eemail']}</td>";

            if($data_set['ecity']=='')
            {
                echo "<td>{$data_set['ecountry']}</td>";
            }
            else
            {
                echo "<td onmouseover=\"ShowText('Message1[$i]'); return true;\" onmouseout=\"HideText('Message1[$i]'); return true;\" href=\"javascript:ShowText('Message1')\">{$data_set['ecity']}</td>";
            }

            // echo "<td>{$data_set['ecountry']},{$data_set['estate']},{$data_set['ecity']}</td>";
            echo "<td>{$qua}</td>";
            echo "<td>{$data_set['other_work1']} {$data_set['other_work2']}{$data_set['other_work3']}{$data_set['other_work4']} {$data_set['other_work5']} {$data_set['other_work6']} {$data_set['other_work7']} {$data_set['other_work8']} {$data_set['other_work9']} {$data_set['other_work10']}
                 {$data_set['other_work1e']} {$data_set['other_work2e']} {$data_set['other_work3e']} {$data_set['other_work4e']} {$data_set['other_work5e']} {$data_set['other_work6e']} {$data_set['other_work7e']} {$data_set['other_work8e']} {$data_set['other_work9e']} {$data_set['other_work10e']}
                </td>";
            echo "<td><a href=\"detailcv.php?id={$data_set['eid']}\" target=\"_blank\"><input  style=\" cursor:hand;width:40px\" class=\"button\" name=\"cv\" type=\"button\" value=\"C V\" /></a></td>";
            echo "</tr>";

            $i++;
        }
    }

?>

查询：在此我获取了selected_val

$query = "SELECT emp.eid,ename,lname,ecell,eposition,eemail,ecountry,estate,ecity,prefcities,ca,cs,cwa,completed,persuing,other_work1,other_work2,other_work3,other_work4,other_work5,other_work6,other_work7,other_work8,sc.selected_val ";   
$query .= "FROM employee emp,selected_candidate sc";

如果循环：

if($data_set['selected_val']=='1')
{
    echo "<script>$('#{$rowid}').css(\"background-color\",\"yellow\");</script>";
}

$rowid++;

selected_candidate Table


 eid  int(30)
    rid int(30)
    selected_val int(1)

employee table also contains eid int(30)

感谢。

Answer 1

错误通常意味着您的查询中存在错误。要获得更多详细信息，请将mysql_query($query)替换为mysql_query($query)or die(mysql_error())。

可能是语法错误或输入错误的列名。

基于从数据库获取的值突出显示行

1 个答案: