如何将json对象名称转换为字符串格式

时间:2013-01-11 07:43:03

标签: javascript jquery json

var Data = {    "1":"United States",
                "2":"United Kingdom",
                "3":"Aruba",
                "4":"United Kingdom",
                "5":"Aruba",
                "6":"Bahrain",
                "7":"United Kingdom",
                "8":"Algeria",
                "9":"Andorra",
                "10":"American Samoa"
}
var IdKeyValuePair = [{"DropD1":Data},{"DropD2":Data},{"DropD3":Data},{"DropD4":Data}];
var obj= {
            id           : IdKeyValuePair,
            MultiColuumn : true,
            Checkbox     : true,
            Pagination   : false,
            max_height   : 400

         };

我想打印DropD1,DropD2的名称.. 我正以这种方式试着。但我无法做到这一点..

var idName = [],i;
idLen = obj.id.length;
for(i=0;i<idLen;i++){
    idName[i] = ''+obj.id[i];
    console.log(idName[i]);
}

我得到DropD1,DropD2 ..但问题是它是一个对象形式,所以我怎么能在一个字符串中转换它... 我想要一个结果是这样的格式...

for(i=0;i<idLen;i++){
   console.log(idName[i]);
}

字符串格式的预期输出不在对象中:

DropD1 DropD2 DropD3

4 个答案:

答案 0 :(得分:0)

试试这个。它对我有用

var IdKeyValuePair = [{ "DropD1": Data["1"] }, { "DropD2": Data["2"] }, { "DropD3": Data["3"]}, { "DropD4": Data["4"]}]; so on and so forth.

答案 1 :(得分:0)

我使用浏览器stringify属性::

获得了一个解决方案
var jsonobj={"name":"George", "age":29, "friends":["John", "Sarah", "Albert"]}
var jsonstr=JSON.stringify(jsonobj)
alert(typeof jsonstr) //string

你可以通过以下方式将它转换为javascript对象::

var jsonstr='{"name":"George", "age":29, "friends":["John", "Sarah", "Albert"]}'
var george=JSON.parse(jsonstr) //convert JSON string into object
alert(george.age)

有关json的更多信息,请参阅以下链接,

http://www.javascriptkit.com/jsref/json.shtml

答案 2 :(得分:0)

试试这个

var idName = [],i;
idLen = obj.id.length;
for(i=0;i<idLen;i++){
    idName[i] = obj.id[i];
}
console.log(idName.join(" "));

答案 3 :(得分:0)

试试这个:

  var Data = {    "1":"United States",
                  "2":"United Kingdom",
                  "3":"Aruba",
                  "4":"United Kingdom",
                  "5":"Aruba",
                  "6":"Bahrain",
                  "7":"United Kingdom",
                  "8":"Algeria",
                  "9":"Andorra",
                  "10":"American Samoa"
  }
  var IdKeyValuePair = [{"DropD1":Data},{"DropD2":Data},{"DropD3":Data},{"DropD4":Data}];
  var obj= {
              id           : IdKeyValuePair,
              MultiColuumn : true,
              Checkbox     : true,
              Pagination   : false,
              max_height   : 400

           };

  var idName = [],i;
  idLen = obj.id.length;
  for(i=0;i<idLen;i++){
    idName[i] = obj.id[i];
    console.info(JSON.stringify(idName[i]));
  }

通过向对象添加空字符串(“”+ object)

,您无需将对象转换为字符串