栅格之外的Java getSubimage()

时间:2013-01-11 01:09:57

标签: java bufferedimage raster

我正在尝试拍摄图像并将其存储在16x16子图像的数组中。我使用的图像是512x512像素。但是,在遍历循环时,getSubimage()会被Raster异常停止。

以下是代码:

public class TileList extends JPanel {

  private static final int width = 16;          //width of a tile
  private static final int height = width;
  private int col = 1;
  private int row = 1;

  private BufferedImage image;
  File tilesetImage = new File("image.png");
  BufferedImage tileset[];

  public void loadAndSplitImage (File loadImage) {
    try{
        image = ImageIO.read(loadImage);
    }catch(Exception error) {
        System.out.println("Error: cannot read tileset image.");
    }// end try/catch
    col = image.getWidth()/width;
    row = image.getHeight()/height;
    tileset = new BufferedImage[col*row];
  }// end loadAndSplitImage

  public TileList() {
    loadAndSplitImage(tilesetImage);
    setLayout(new GridLayout(row,col,1,1));
    setBackground(Color.black);

    int x=0;
    int y=0;
    int q=0;                                    //keeps track of tile #
    for (int i = 0; i < row; i++) {

        for (int j = 0; j < col; j++) {
            JPanel panel = new JPanel();
            tileset[q] = new BufferedImage(width, height, image.getType());
            tileset[q] = image.getSubimage(x,y,x + width,y + height);
            panel.add(new JLabel(new ImageIcon(tileset[q])));
            add(panel);
            x += width;
            q++;
        }// end for loop
        y += height;
        x = 0;
    }// end for loop
  }// end constructor
}// end class

这是错误:

Exception in thread "AWT-EventQueue-0" java.awt.image.RasterFormatException: (x
+ width) is outside of Raster
    at sun.awt.image.ByteInterleavedRaster.createWritableChild(ByteInterleav
edRaster.java:1245)
    at java.awt.image.BufferedImage.getSubimage(BufferedImage.java:1173)
    at TileList.<init>(TileList.java:59)
    at TileList.createAndShowGui(TileList.java:79)
    at TileList$1.run(TileList.java:88)
    at java.awt.event.InvocationEvent.dispatch(InvocationEvent.java:251)
    at java.awt.EventQueue.dispatchEventImpl(EventQueue.java:721)
    at java.awt.EventQueue.access$200(EventQueue.java:103)
    at java.awt.EventQueue$3.run(EventQueue.java:682)
    at java.awt.EventQueue$3.run(EventQueue.java:680)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDo
main.java:76)
    at java.awt.EventQueue.dispatchEvent(EventQueue.java:691)
    at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThre
ad.java:244)
    at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.
java:163)
    at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThre
ad.java:151)
    at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:147)

    at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:139)

    at java.awt.EventDispatchThread.run(EventDispatchThread.java:97)

2 个答案:

答案 0 :(得分:9)

您将错误的参数传递给getSubimage。文档说......

  

参数:
      x - 指定矩形区域左上角的X坐标       y - 指定矩形区域左上角的Y坐标
      w - 指定矩形区域的宽度
      h - 指定矩形区域的高度

您传递的是x, y, x + width, y + width,这意味着如果x = 256,width实际上等于256 + 16 = 272

因此,您的新图片将是... x + width = 256 + 272 = 528,它比图片区域宽。

你应该通过x, y, width, heigh

tileset[q] = image.getSubimage(x, y, width, height);

答案 1 :(得分:0)

来自javadoc

* @param x the X coordinate of the upper-left corner of the
*          specified rectangular region
* @param y the Y coordinate of the upper-left corner of the
*          specified rectangular region
* @param w the width of the specified rectangular region
* @param h the height of the specified rectangular region

这意味着以下行错误

image.getSubimage(x,y,x + width,y + height);

它应该像

image.getSubimage(x, y, width, height);

有关完整的工作示例,请查看此paste