我正在尝试拍摄图像并将其存储在16x16子图像的数组中。我使用的图像是512x512像素。但是,在遍历循环时,getSubimage()会被Raster异常停止。
以下是代码:
public class TileList extends JPanel {
private static final int width = 16; //width of a tile
private static final int height = width;
private int col = 1;
private int row = 1;
private BufferedImage image;
File tilesetImage = new File("image.png");
BufferedImage tileset[];
public void loadAndSplitImage (File loadImage) {
try{
image = ImageIO.read(loadImage);
}catch(Exception error) {
System.out.println("Error: cannot read tileset image.");
}// end try/catch
col = image.getWidth()/width;
row = image.getHeight()/height;
tileset = new BufferedImage[col*row];
}// end loadAndSplitImage
public TileList() {
loadAndSplitImage(tilesetImage);
setLayout(new GridLayout(row,col,1,1));
setBackground(Color.black);
int x=0;
int y=0;
int q=0; //keeps track of tile #
for (int i = 0; i < row; i++) {
for (int j = 0; j < col; j++) {
JPanel panel = new JPanel();
tileset[q] = new BufferedImage(width, height, image.getType());
tileset[q] = image.getSubimage(x,y,x + width,y + height);
panel.add(new JLabel(new ImageIcon(tileset[q])));
add(panel);
x += width;
q++;
}// end for loop
y += height;
x = 0;
}// end for loop
}// end constructor
}// end class
这是错误:
Exception in thread "AWT-EventQueue-0" java.awt.image.RasterFormatException: (x
+ width) is outside of Raster
at sun.awt.image.ByteInterleavedRaster.createWritableChild(ByteInterleav
edRaster.java:1245)
at java.awt.image.BufferedImage.getSubimage(BufferedImage.java:1173)
at TileList.<init>(TileList.java:59)
at TileList.createAndShowGui(TileList.java:79)
at TileList$1.run(TileList.java:88)
at java.awt.event.InvocationEvent.dispatch(InvocationEvent.java:251)
at java.awt.EventQueue.dispatchEventImpl(EventQueue.java:721)
at java.awt.EventQueue.access$200(EventQueue.java:103)
at java.awt.EventQueue$3.run(EventQueue.java:682)
at java.awt.EventQueue$3.run(EventQueue.java:680)
at java.security.AccessController.doPrivileged(Native Method)
at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDo
main.java:76)
at java.awt.EventQueue.dispatchEvent(EventQueue.java:691)
at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThre
ad.java:244)
at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.
java:163)
at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThre
ad.java:151)
at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:147)
at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:139)
at java.awt.EventDispatchThread.run(EventDispatchThread.java:97)
答案 0 :(得分:9)
您将错误的参数传递给getSubimage
。文档说......
参数:
x - 指定矩形区域左上角的X坐标 y - 指定矩形区域左上角的Y坐标
w - 指定矩形区域的宽度
h - 指定矩形区域的高度
您传递的是x, y, x + width, y + width
,这意味着如果x
= 256,width
实际上等于256 + 16 = 272
。
因此,您的新图片将是... x + width = 256 + 272 = 528
,它比图片区域宽。
你应该通过x, y, width, heigh
tileset[q] = image.getSubimage(x, y, width, height);
答案 1 :(得分:0)
来自javadoc
* @param x the X coordinate of the upper-left corner of the
* specified rectangular region
* @param y the Y coordinate of the upper-left corner of the
* specified rectangular region
* @param w the width of the specified rectangular region
* @param h the height of the specified rectangular region
这意味着以下行错误
image.getSubimage(x,y,x + width,y + height);
它应该像
image.getSubimage(x, y, width, height);
有关完整的工作示例,请查看此paste