Question

所以我有一堆基本上可以进行相同调用的方法，唯一的区别是泛型的类名。例如：

电流：

public void methodA(ARequest request, ADelegate delegate)
{
     JsonClient<ARequest, AResponse> client = new JsonClient<ARequest, AResponse>(request.ServiceServerUrl, request, new AResponse());
     client.sendRequest(delegate);
}

public void methodB(BRequest request, BDelegate delegate)
{
         JsonClient<BRequest, BResponse> client = new JsonClient<BRequest, BResponse>(request.ServiceServerUrl, request, new BResponse());
         client.sendRequest(delegate);
}

我想做的是：

private void serviceCall<R extends RequestBase, S extends ResponseBase>(ADelegate delegate)
{
    JsonClient<R, S> client = new JsonClient<R, S>(request.ServiceServerUrl, request, new AResponse());
    client.sendRequest(delegate);
}

public void methodA(ARequest request, ADelegate delegate)
{
    serviceCall<ARequest, AResponse>(delegate);
}

public void methodB(BRequest request, BDelegate delegate)
{
    serviceCall<BRequest, BResponse>(delegate);
}

我认为这在C＃中是可行的，但我只想知道如何在Java中正确地做到这一点。

编辑：为清楚起见。

Answer 1

您应该能够写下以下内容：

private <R extends RequestBase, S extends ResponseBase> void serviceCall(
        R request,
        S response,
        ADelegate delegate
) {
    JsonClient<R, S> client = new JsonClient<R, S>(request.ServiceServerUrl, request, response);
    client.sendRequest(delegate);
}

请注意，调用者必须实例化并传入response，因为Java中不可能使用new S()之类的东西：

public void method(ARequest request, ADelegate delegate) {
    serviceCall(request, new AResponse(), delegate);
}

像

这样的东西

MyClass.<ARequest, AResponse>serviceCall(request, new AResponse(), delegate)

这里没有必要

因为编译器会为你推断出类型参数。

Answer 2

你的意思是？

public <T extends RequestBase, E extends ResponseBase> void method(T request, E delegate)
{
     JsonClient<T, E> client = new JsonClient<T, E>(request.ServiceServerUrl, request, new AResponse());
     client.sendRequest(delegate);
}

并像ClassName.<ARequest, AResponse>method(request, response)一样调用它。

Java泛型作为参数

2 个答案: