Question

我在网上四处寻找这个答案，所以我很抱歉，如果它在某处。下面的这个脚本工作正常，除了它返回.DS_Store文件的事实我如何从这个查询和所有其他隐藏文件中排除它，但因为我在我的脚本中创建了唯一的文件夹.DS_Store < / p>

告诉应用程序“系统事件” 将listOfInputs设置为文件夹a的每个磁盘项的POSIX路径作为列表结束告诉

以下是完整的脚本。我在创建文件后将文件放入文件夹中，但最终会在创建之前提示文件。

运行

tell application "Finder"
    if not (exists folder "IN") then
        make new folder at desktop with properties {name:"IN"}
    end if
    if not (exists folder "OUT") then
        make new folder at desktop with properties {name:"OUT"}
    end if
end tell


set theINfolder to path to the desktop as string
set a to theINfolder & "IN:"


tell application "System Events"
    set listOfInputs to POSIX path of every disk item of folder a as list
end tell

set inputs to listOfInputs

set theOutfolder to path to the desktop as string
set outputFolder to theOutfolder & "OUT:"

set params to {}

main(inputs, outputFolder, params)

结束

Answer 1

以下内容可行：

set listOfInputs to list folder a without invisibles

但without invisibles无法与POSIX path结合使用，因此我们使用循环代替：

set listOfInputs to {}
tell application "System Events"
    set the_items to list folder a without invisibles
    repeat with i from 1 to the count of the_items
        set this_item to alias ((a as Unicode text) & (item i of the_items))
        set end of listOfInputs to POSIX path of this_item
    end repeat
end tell

Answer 2

列表文件夹命令已被弃用，可能会意外停止工作。

尝试：

set inFolder to (path to desktop as text) & "IN"
do shell script "mkdir -p " & quoted form of (POSIX path of inFolder)
set listOfInputs to paragraphs 2 thru -1 of (do shell script ("find " & quoted form of (POSIX path of inFolder) & " \\! -name \".*\""))

您可以将结果作为由空格分隔的字符串获取，如下所示：

set inFolder to (path to desktop as text) & "IN"
do shell script "mkdir -p " & quoted form of (POSIX path of inFolder)
set {TID, text item delimiters} to {text item delimiters, " "}
set listOfInputs to paragraphs 2 thru -1 of (do shell script ("find " & quoted form of (POSIX path of inFolder) & " \\! -name \".*\"")) as text
set text item delimiters to TID

Applescript系统事件返回.DS_Store - 我如何忽略

2 个答案: