这里我有一个java脚本,它将根据document.write(makeCalendar(2013,0))
中选择的年份和月份构建日历。第一个参数是年份,第二个参数是月份。
我已经工作到了那一天,它只显示当天的日历事件但是无法在我的HolidayName[]
中显示剩余的日期。这是我的数组和循环以显示事件,尽管将添加新事件稍后的。它只能显示第一个日期,我不明白为什么因为它应该一直循环。下面是我的循环,然后是javascript。
var HolidayName = new Array (0, 1, "New Years Day",6, 1, "Canada Day",11, 25, "Christmas Day",11, 26, "Boxing Day")
function getHoliday(month, day)
{
for(var index = 0; HolidayName.length > index; index++)
{
if(HolidayName[index] == month && HolidayName[index+1] == day)
{
var name = HolidayName[index+2]
}
else
{
return ""
}
return name
}
}
以下是代码,该事件将在功能getHoliday(mth, dayCtr)
function leapYear(yr) {
if (yr < 1000) yr+=1900
return((yr%4 == 0) && ((yr%100 == 0) || (yr%400 ==0)))
}
function startCol(width, height, color){
return('<TD WIDTH=' + width + ' HEIGHT=' + height + '>' + '<FONT COLOR="' + color + '">');
}
function makeCalendar(yr, mth){
var months = new Array("Jan", "Feb", "Mar", "Apr", "May", "June", "July", "Aug", "Sept", "Oct", "Nov", "Dec")
var days = new Array(31, leapYear(yr)?29:28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31)
var weekDays = new Array("Sun", "Mon", "Tues", "Wed", "Thurs", "Fri", "Sat")
var HolidayName = new Array (0, 1, "New Years Day",6, 1, "Canada Day",11, 25, "Christmas Day",11, 26, "Boxing Day")
function getHoliday(month, day)
{
for(var index = 0; HolidayName.length > index; index++)
{
if(HolidayName[index] == month && HolidayName[index+1] == day)
{
var name = HolidayName[index+2]
}
else
{
return ""
}
return name
}
}
var mthSz = days[mth]
var mthName = months[mth]
var firstDyofMnth = new Date(yr, mth, 1)
var firstDay = firstDyofMnth.getDay() + 1
var numRows = Math.ceil((mthSz + firstDay-1)/7)
var mthNameHeight = 50
var borderWidth = 2
var cellSpacing = 4
var cellHeight = 80
var hdrColor = "midnightblue"
var hdrSz = "+3"
var colWidth = 100
var dayCellHeight = 25
var dayColor = "black"
var dayCtr = 1
// Build the HTML Table
var txt = '<CENTER>'
txt += '<TABLE BORDER=' + borderWidth + ' CELLSPACING=' + cellSpacing + '>'
//Show Month Name and Year
txt += '<TH COLSPAN=7 HEIGHT=' + mthNameHeight + '>'
txt += '<FONT COLOR="' + hdrColor + '" SIZE=' + hdrSz + '>'
txt += mthName + ' ' + year + '</FONT>' + '</TH>'
// Show Days of the Week
txt += '<TR ALIGN="center" VALIGN="center">'
for (var dy = 0; dy < 7; ++dy) {
txt += startCol(colWidth, dayCellHeight, dayColor) + weekDays[dy] + '</FONT></TD>'
}
txt += '</TR>'
// Show Dates in Calendar
for (var row=1; row <= numRows; ++row) {
txt += '<TR ALIGN="right" VALIGN="top">'
for (var col = 1; col <= 7; ++col) {
if (((col < firstDay) && (row==1)) || (dayCtr>mthSz))
{txt += '<TD BGCOLOR="Gainsboro"><BR></TD>'}
else
{
txt += '<TD HEIGHT=' + cellHeight + '><FONT COLOR="' + dayColor + '"> <B>'
txt += dayCtr
txt += '</B></FONT><BR>' + getHoliday(mth,dayCtr) + '</TD>'
dayCtr++;
}
}
txt += '</TR>'
}
// close all basic table tags and output txt string
txt += '</TABLE></CENTER>'
document.write(txt)
}
答案 0 :(得分:0)
因为您有else { return "" }
,然后在if...else
语句之外return name
。因此,无论条件是真还是假,您的函数将在循环的第一次运行期间终止,如果条件为真则返回名称,否则返回空字符串。
另外,我认为你需要在每个循环中将索引增加3而不是1;并且你应该使用分号来结束每一行(除非它是{}块的开头或结尾。)
var HolidayName = new Array(0, 1, "New Years Day", 6, 1, "Canada Day", 11, 25, "Christmas Day", 11, 26, "Boxing Day");
function getHoliday(month, day) {
for (var index = 0; index + 2 < HolidayName.length; index+=3) {
if (HolidayName[index] == month && HolidayName[index + 1] == day) {
return HolidayName[index + 2];
}
}
return '';
}