我正在使用Excel 2007,它支持最多16,384列的列。我想获得列名对应的列号。
目前,我使用以下代码。但是,此代码最多支持256列。如果列号大于256,任何想法如何获取列名。
function loc = xlcolumn(column)
if isnumeric(column)
if column>256
error('Excel is limited to 256 columns! Enter an integer number <256');
end
letters = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
count = 0;
if column-26<=0
loc = char(letters(column));
else
while column-26>0
count = count + 1;
column = column - 26;
end
loc = [char(letters(count)) char(letters(column))];
end
else
letters = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'];
if size(column,2)==1
loc =findstr(column,letters);
elseif size(column,2)==2
loc1 =findstr(column(1),letters);
loc2 =findstr(column(2),letters);
loc = (26 + 26*loc1)-(26-loc2);
end
end
由于
答案 0 :(得分:2)
作为转移,这里是一个全函数句柄示例,(几乎)不需要基于文件的函数。这基于dec2base
函数,因为Excel列名称(几乎)是26个基数,但没有“0”字符,这是令人沮丧的差异。
注意:这可能是一个糟糕的想法,但它确实有效。更好的解决方案可能在文件交换的其他地方找到。
首先,我无法绕过一个基于文件的函数,执行任意深度函数组合。
function result = compose( fnHandles )
%COMPOSE Compose a set of functions
% COMPOSE({fnHandles}) returns a function handle consisting of the
% composition of the cell array of input function handles.
%
% For example, if F, G, and H are function handles with one input and
% one output, then:
% FNCOMPOSED = COMPOSE({F,G,H});
% y = FNCOMPOSED(x);
% is equivalent to
% y = F(G(H(x)));
if isempty(fnHandles)
result = @(x)x;
elseif length(fnHandles)==1
result = fnHandles{1};
else
fnOuter = fnHandles{1};
fnRemainder = compose(fnHandles(2:end));
result = @(x)fnOuter(fnRemainder(x));
end
然后,将base26值转换为正确的字符串
的奇异,人为的路径%Functions leading to "getNumeric", which creates a numeric, base26 array
remapUpper = @(rawBase)(rawBase + (rawBase>='A')*(-55)); %Map the letters 'A-P' to [10:26]
reMapLower = @(rawBase)(rawBase + (rawBase<'A')*(-48)); %Map characters '0123456789' to [0:9]
getRawBase = @(x)dec2base(x, 26);
getNumeric = @(x)remapUpper(reMapLower(getRawBase(x)));
%Functions leading to "correctNumeric"
% This replaces zeros with 26, and reduces the high values entry by 1.
% Similar to "borrowing" as we learned in longhand subtraction
borrowDownFrom = @(x, fromIndex) [x(1:(fromIndex-1)) (x(fromIndex)-1) (x(fromIndex+1)+26) (x((fromIndex+2):end))];
borrowToIfNeeded = @(x, toIndex) (x(toIndex)<=0)*borrowDownFrom(x,toIndex-1) + (x(toIndex)>0)*(x); %Ugly numeric switch
getAllConditionalBorrowFunctions = @(numeric)arrayfun(@(index)@(numeric)borrowToIfNeeded(numeric, index),(2:length(numeric)),'uniformoutput',false);
getComposedBorrowFunction = @(x)compose(getAllConditionalBorrowFunctions(x));
correctNumeric = @(x)feval(getComposedBorrowFunction(x),x);
%Function to replace numerics with letters, and remove leading '@' (leading
%zeros)
numeric2alpha = @(x)regexprep(char(x+'A'-1),'^@','');
%Compose complete function
num2ExcelName = @(x)arrayfun(@(x)numeric2alpha(correctNumeric(getNumeric(x))), x, 'uniformoutput',false)';
现在使用一些压力转换进行测试:
>> num2ExcelName([1:5 23:28 700:704 727:729 1024:1026 1351:1355 16382:16384])
ans =
'A'
'B'
'C'
'D'
'E'
'W'
'X'
'Y'
'Z'
'AA'
'AB'
'ZX'
'ZY'
'ZZ'
'AAA'
'AAB'
'AAY'
'AAZ'
'ABA'
'AMJ'
'AMK'
'AML'
'AYY'
'AYZ'
'AZA'
'AZB'
'AZC'
'XFB'
'XFC'
'XFD'
答案 1 :(得分:0)
我写的这个函数适用于任意数量的列(直到Excel用完列)。它只需要一个列号输入(例如16368将返回一个字符串&#39; XEN&#39;)。
如果这个概念的应用与我的功能不同,重要的是要注意x列的A列每26 ^(x-1)+ 26 ^(x-开始) 2)+ ... + 26 ^ 2 + 26 + 1.(例如&#39; AAA&#39;开始于26 ^ 2 + 26 + 1 = 703)
function [col_str] = let_loc(num_loc)
test = 2;
old = 0;
x = 0;
while test >= 1
old = 26^x + old;
test = num_loc/old;
x = x + 1;
end
num_letters = x - 1;
str_array = zeros(1,num_letters);
for i = 1:num_letters
loc = floor(num_loc/(26^(num_letters-i)));
num_loc = num_loc - (loc*26^(num_letters-i));
str_array(i) = char(65 + (loc - 1));
end
col_str = strcat(str_array(1:length(str_array)));
end
希望这能节省一些时间!